Given f(x)=x-5/3 solve f^-1(3)

The sum of two consecutive odd numbers is 64. Name the numbers.

Marta_Voda [28]

Answer:

31 and 33

Step-by-step explanation:

Odd numbers are apart by 2: 1, 3, 5, 7, for example.

1. x + (x+2) = 64

2. 2x + 2 = 64

3. x = 31

4. 31 + (31 + 2) = 64

5 0

3 years ago

In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist

vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

= 0.04e-0.5 = 0.04/√e

= 0.04/1.6487

= 0.0292

Thus, Cov(X, Y) =0.029.

5 0

3 years ago

Look at image. reflection across x=1

elena-14-01-66 [18.8K]

Answer:

A' would be at (0,-4)

B' would be at (-2,1)

C' would be at (-2,-3)

Step-by-step explanation:

A' would be at (0,-4)

B' would be at (-2,1)

C' would be at (-2,-3)

5 0

3 years ago

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Consider the quadratic function f(x)=−x^2+x+30

yaroslaw [1]

Answer:

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The yy-intercept is $y = 30$ .

Step-by-step explanation:

Given a quadratic function in the following format:

$f(x) = ax^{2} + bx + c = 0, a \neq 0$

The x-values of the x-intercepts are $x_{1}, x_{2}$ , given by the following formulas.

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

We have that:

$f(x) = -x^{2} + x + 30$

This is not in the format above. I will multiply by (-1), so we have:

$f(x) = x^{2} - x - 30$

So, $a = 1, b = -1, c = -30$

$\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6$

$x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5$

This means that

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The y-intercept is the value of f(x) when x = 0. So

$f(x)=−x^{2}+x+30$

$f(0) = 30$

The yy-intercept is $y = 30$ .

5 0

3 years ago

Max used 3 7/8 pounds of yellow potatoes and 2 5/8 pounds of sweet potatoes to make a potato salad. How many more pounds of yell

Talja [164]

Answer:

3 7/8-2 5/8

31-21

8

=10/8

=1 1/4 more

5 0

3 years ago

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