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marishachu [46]
3 years ago
11

Ten years ago, Rapunzel's hair was 19 long. Now her hair is 20193 long. Approximately how many times as long is Rapunzel's hair

now as it was ten years ago?
A. 1x10^3
B. 2x10^3
C. 1x10^5
D. 2x10^5

Mathematics
1 answer:
vladimir2022 [97]3 years ago
8 0

Answer:

A.

Step-by-step explanation:

if you simplify the equation on A., you'll get 1,000 as the number.  Rapunzel's hair was approximately 1,000 times longer than it was 10 years ago.

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What is necessary to determine the z-score for a raw score in a particular set of scores?.
Xelga [282]

Answer:

See below

Step-by-step explanation:

The mean score and the standard deviation are needed

7 0
2 years ago
The solution to the system equations
katovenus [111]

Let's solve this system of equations through substitution.

We have these two equations.

-7x-2y=14

6x+6y=18

Now let divide the second equation by 6.

6x+6y=18 ---->   x+y=3

Next, let us move y to the right side of the equation.

x+y=3 -------> x=3-y (x equals 3-y)

Because we found out that what x is in terms of y, we can input that in for every instance of x in this equation below.

-7x-2y=14 becomes -7(3-y)-2y=14 (Why? Because x equals 3-y!)

We have a one variable equation now and can solve for y.

-7(3-y)-2y=14

-21+7y-2y=14

5y=35

y=7

Plug in 7 for y in any equation to find x.

x+y=3

x+7=3

x=-4

answer: x=-4, y=7

3 0
3 years ago
A square has a side length of 2.5 feet if the square is dilated by a factor of 2.5 what is the length of a side of the new squar
Anni [7]

Answer:

6.25

Step-by-step explanation:

You would multiply 2.5 by itself since you're dilating your side length.

6 0
3 years ago
Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

3 0
3 years ago
Solve for y: 4-(y-5)-(y+3)=2<br> A.25\2 <br> B.-5<br> C.2<br> D.19\5
Dafna11 [192]

Answer: My answer would be 2

3 0
3 years ago
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