The dimensions of the crate that will minimize the total cost of material are 10, 10, and 29.
<h3>How to compute the dimension?</h3>
The volume will be:
= Length × Width × Height
= lwh
For the square base, w = l
2880 = w²h
The cost function will be:
C = 12wl + 4wh + 4lh
Put l = w.
C = 12w² + 8wh
C = 12w² + 8w(2880/w²)
C = 12w² + 23040/w
Differentiate with respect to w
C'(w) = 0
24w = 23040/w²
24w³ = 23040
w³ = 960
w = 10 approximately
The length is 16 as well as they are the same. The height will be:
= 2880/w²
= 2880/10²
= 28.8 = 29
Therefore, the dimensions are 10, 10, and 29.
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Let's apply the formula giving the slope:
m=(y2-y1) /(x2-x1) , let's plug:
m= (8-0) / (3-(-1)) ====> m= 2
Answer:
12 14/23
Step-by-step explanation:
1 2 + 1 4 ÷ 2 3
according to PEMDAS
we have to divide before we add
12 + (14/23)
12 14/23
Answer:
1. Lets say that you get the coords. (1,2). X would be the first one (1), and Y would be the second number (2). if you got 2/1, then, because of rise/run, that 2 would be Y and 1 would be X
2. ?
3. Slope is rise/run (Y/X), and the Y intercept is where the line intercepts the Y axis.
I literally have no idea how to answer 2, but I hope that I helped a bit :)