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Dahasolnce [82]
3 years ago
13

The question is down bellow

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

1. 6.05

Standard Form: 65

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Which shows one way to determine the factors of x3 11x2 – 3x – 33 by grouping? x2(x 11) 3(x – 11) x2(x – 11) – 3(x – 11) x2(x 11
Aloiza [94]

The one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

<h3>What is a factorization?</h3>

It is the method to separate the polynomial into parts and the parts will be in multiplication. And the value of the polynomial at this point will be zero.

The steps involved in the factorization are;

1. For each pair of parentheses, we create a common factor.

2. We use x2 as a common factor for the first parenthesis.

3. We use common factor 3 for the second parenthesis.

x^3  + 11x^2 - 3x -33 \\\\ x^2(x+11)-3(x+11)_

We will find the final solution as x^2(x+11)-3(x+11)_.

Hence the one way to determine factors of x³  + 11x² – 3x – 33  will be x^2(x+11)-3(x+11)_.

To learn more about the factorization refer to the link;

brainly.com/question/24182713

3 0
2 years ago
How do you simplify a math problem?
STatiana [176]

idk what kind of math problem but, if its just simple id us PEMDAS

3 0
3 years ago
Read 2 more answers
*will give brainlist**okay so u want to know how much diapers u will use for 3 years basically and then the details to help u ea
pochemuha

ok so divide 1500 by 250 to determine how many boxes you need to by in 1 year

so that equals 6 then you multiply that by $30 to find the total cost of all the diapers per year so the is $180 per year and then multiply that by 3 to find the cost of all 3 years

So the answer is you will spend $540 in total

8 0
3 years ago
Which expression is equivalent to (sf)(6)
SashulF [63]

Answer:

(st)(6)= s(6) * t(6)

Step-by-step explanation:

(st)(6)

(st)(x)= s(x) * t(x) we multiply it

(st)(6)= s(6) * t(6)

Hope this helps.

4 0
2 years ago
Need help finding a constant k at which the function is continuous everywhere.
saveliy_v [14]

Answer:

k = -6/35

Step-by-step explanation:

To make the function continuous

kx^2 = x+k

These must be equal where the function is defined for two different intervals

This is at the point x=-6  so let x=-6

k(-6)^2 = -6+k

36k = -6+k

Subtract k from each side

36k-k = -6+k-k

35k = -6

Divide by 35

35k/35 = -6/35

k = -6/35


3 0
2 years ago
Read 2 more answers
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