➻ In a group of 40 people, 27 can speak English and 25 can speak Spanish.
➻ The required number of people who can speak both English and Spanish .
<u>Consider</u> ,
➻ A → Set of people who speak English.
➻ B → Set of people who speak Spanish
➻ A∩B → Set of people who can speak both English and Spanish
➻ n(A∪B) = n(A) + n (B) - n(A∩B)
➻ 40 = 27 + 25 - n (A∩B)
➻ 40 = 52 - n (A∩B)
➻ n (A∩B) = 52 - 40
➻ ∴ n (A∩B) = 12
∴ Required Number of persons who can speak both English and Spanish are <u>12 .</u>
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➻ n(A∪B) = n(A) + n (B) - n(A∩B)
➻ 40 = 27 + 25 - 12
➻ 40 = 52 - 12
➻ 40 = 40
➻ ∴ L.H.S = R.H.S
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Answer:
$1.35
Step-by-step explanation:
x: quarter=$0.25
y: dime=$0.10
z: nickel=$0.05
so total amount of changes
= (0.25*x)+(0.10*y)+(0.05*z)
x=3, y=5, z=2
substituting into the eqn
total = (0.25*3)+(0.10*5)+(0.05*2)
= 0.75 + 0.5 + 0.1
= $1.35
Answer:Yes
Step-by-step explanation:
Answer: 
Step-by-step explanation:
Consider 
Substitute t= sinx
then dt = cos x dx

![[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]](https://tex.z-dn.net/?f=%5B%5Cint%20x%5Endx%3D%5Cdfrac%7Bx%5E%7Bn%2B1%7D%7D%7Bn%2B1%7D%2BC%5D)

Hence, 