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3 years ago

7

Using the expression below, choose the correct answers for the new balance and amount of interest earned in the following compou

nd interest problem.
P(1 + r)n

$1,100 at 8%, for 15 years, compounded annually.

Total Amount = $
Interest Amount = $

1 answer:

Ivanshal [37]3 years ago

4 0

Total = Principal * (1 + rate)^years
Total = 1,100 * (1.08)^15
Total = 3,489.39

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If the gradient of the line joining the points (-3,-7) and (4,p) is 3/5, find the value of P.

adelina 88 [10]

Given:

Two points (-3, -7) and (4, p).

To find the value of P if the gradient is 3/5:

The gradient in a linear equation is the same thing as the slope of the line.

So, the formula is,

$\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \frac{3}{5}=\frac{p-(-7)}{4-(-3)} \\ \frac{3}{5}=\frac{p+7}{7}\Rightarrow3(7)=5(p+7) \\ 21=5p+35 \\ 5p=21-35 \\ 5p=-14 \\ p=-2.8 \end{gathered}$

Hence, the value of p is -2.8.

4 0

1 year ago

Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

4 years ago

Help im almost finished

blagie [28]

59aaaaaaaaaaaaaaaaaa

6 0

3 years ago

Given the trinomial, what is the value of the coefficient B in the factored form? 2x2 14xy − 36y2 = 2(x By)(x − 2y) 18 9 −9 −18.

Finger [1]

The value of the coefficient B will be 9.

<h3>What will be the value of B in equation written below?</h3>

2(x+By)(x-2y)

=2(x^2 -2xy +Bxy -2By^2)

=2x^2 -4xy + 2Bxy - 4By^2

The original form is $\d2x^{2} +14x-36y^{2}$

$2(x+By)(x-2y)\\\ =2(x^2 -2xy +Bxy -2By^2)\\\\ =2x^2 -4xy + 2Bxy - 4By^2\\\\2x^2 + 14xy - 36y^2\\\\ -36y^2 = -4By^2B= 9\\\\ -4xy +2Bxy= 14xy\\\\xy(-4 +2B)= 14xy\\\\ -4 + 2B = 14\\\\ 2B = 18\\\ B=9$

hence the value of B=9

To know more about trinomial follow

brainly.com/question/1538726

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2 years ago

It’s as light as a feather, but the strongest person can’t hold it for more than five minutes. What is it?

Makovka662 [10]

Answer:

Air? Their breath?

5 0

4 years ago

Read 2 more answers