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3 years ago

Can someone please check this (#4) for me?

Mathematics

1 answer:

IrinaVladis [17]3 years ago

3 0

Answer:

What you are doing wrong is that you are using the formula to find the area of the entire circle rather than using the formula to find a sector of a circle. The two cases uses 2 different kind sentences of formulas.

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La ecuación de la recta que pasa por los puntos (2,-1) y (1,-5) es:

77julia77 [94]

Given:

A line passes through the points (2,-1) and (1,-5).

To find:

The equation of the line.

Solution:

If a line passes through the two points, then the equation of the line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

$y-(-1)=\dfrac{-5-(-1)}{1-2}(x-2)$

$y+1=\dfrac{-5+1}{-1}(x-2)$

$y+1=\dfrac{-4}{-1}(x-2)$

$y+1=4(x-2)$

Using distributive property, we get

$y+1=4(x)+4(-2)$

$y+1=4x-8$

Subtract 1 from both sides.

$y+1-1=4x-8-1$

$y=4x-9$

Therefore, the correct option is B.

5 0

3 years ago

What is the length of the hypoyenuse of a right triangle if each of the two legs is 4 units?

frosja888 [35]

5.65685 should work

4 0

3 years ago

A line passes through (-1,7)and(2, 10)

kumpel [21]

Slope
m = (y2-y1)/(x2-x1)
m = (10 - 7)/(2 --1)
m = 3/3
m = 1

To find the equation
y = mx + b
m is slope
y = 1x + b
plug in one of the equations to solve for b
10 = 1(2) + b
10 = 2 + b
subtract 2 from both sides
8 = b

The equation is
y = 1x + 8
or you can write it as
y = x + 8

Hope this helps

3 0

3 years ago

Solve for x<br> logx+log(x-4)=2log5

sleet_krkn [62]

$\log{x} + \log{(x-4)} = 2 \log{5}\\\\
\log{\big(x(x-4)\big)} = \log{5^2}\\\\
\log{(x^2-4x)} = \log{25} \\\\
x^2-4x = 25\\\\
x^2-4x-25=0 \\\\
x = \frac{4 \pm\sqrt{16+100}}{2} \\\\
x = \frac{4\pm2\sqrt{29}}{2} \\\\
x = 2 \pm \sqrt{29} \\\\
\text{But } x > 0 \implies x = 2 + \sqrt{29}$