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Alex777 [14]
3 years ago
15

Can you please help me ​

Mathematics
2 answers:
larisa [96]3 years ago
7 0
Its B. -2, square root of 5 (2.2), 4, 3^2 (9)
zimovet [89]3 years ago
4 0

I'm sorry if this is incorrect, but I think the answer is -2, \sqrt{5}, 4, 3^2

Explanation: A negative number will always be the least. 3 squared is actually 3*3 and that would be 9. The square root of 5 is 2.2360679775 which is less than 4 so that would go in the second place. I hope this makes sense! :)

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Find an equation of the plane. the plane through the point (−5, 9, 10) and perpendicular to the line x = 1 + t, y = 4t, z = 2 −
PtichkaEL [24]
The direction vector of the line
L: x=1+t, y=4t, z=2-3t
is <1,4,-3>
which is also the required normal vector of the plane.

Since the plane passes through point (-5,9,10), the required plane is :
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3 0
4 years ago
2(x-1) ≥ 10 or 3-4x &gt; 15<br> Solve the compound inequality, and show work!
Veseljchak [2.6K]

Answer:

x\geq 6\text{ or } x

Step-by-step explanation:

We have the compound inequality:

2(x-1)\geq10\text{ or } 3-4x>15

Let's solve each of them individually first:

We have:

2(x-1)\geq10

Divide both sides by 2:

x-1\geq5

Add 1 to both sides:

x\geq6

We have:

3-4x>15

Subtract from both sides:

-4x>12

Divide both sides by -4:  

x

Hence, our solution set is:

x\geq 6\text{ or } x

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