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PSYCHO15rus [73]
3 years ago
5

ABC is a triangle and PQ is parallel to BC.BC=12.6cm, PQ=8.4 cm and AQ= 7.2 cm.Find AC​

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

With a line parallel to a side through a triangle we get similar triangles so a proportion.

AC : BC = AQ : PQ

AC = BC AQ / PQ

AC = 12.6 (7.2) / 8.4

AC = 10.8 cm

Answer: 10.8 cm

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Step-by-step explanation:

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4 years ago
What are all real square roots of .027​
mario62 [17]

Answer:

Step-by-step explanation:

The principal, real, root of:

^{2} \sqrt{0.027}

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0.164316767

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3 years ago
Choose the problem with the same relationship that is modeled by the graph.
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C. Omar walks 22 and one-half blocks to school every day.

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6 0
3 years ago
Read 2 more answers
Need help plz thanks​ for the help
andrew-mc [135]

Answer:

m<C = 66°

Step-by-step explanation:

Perpendicular bisector, AB divides angle CAD into two equal parts. Therefore:

(5x + 9)° = (7x + 3)°

Solve for x

5x + 9 = 7x + 3

Collect like terms

5x - 7x = -9 + 3

-2x = -6

Divide both sides by -2

x = 3

✔️m<C + m<CBA + m<BAC = 180° (sum of triangle)

m<C + 90° + (7x + 3)° = 180 (substitution)

Plug in the value of x and solve

m<C + 90 + 7(3) + 3 = 180

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6 0
3 years ago
Find the exact value of csc ø, if cos ø= 1/9; 180° less ø less than 270°
Iteru [2.4K]

Answer:

The answer to your question is: the first option  - 9/ \sqrt{80}

Step-by-step explanation:

Process

          cosФ = adjacent side / hypotenuse

          -1/9 = adjacent side / hypotenuse

          adjacent side = -1    hypotenuse = 9

          c² = a² + b²

          b² = c² - a²

           b² = 81 - 1

           b = \sqrt{80} \\    b = opposite side

But b is negative because we are in the third quadrant.

          b = -\sqrt{80}

Finally   csc Ф = hypotenuse / opposite side

             csc Ф = - 9 / \sqrt{80}

4 0
3 years ago
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