Question

Find the value of the spring constant for the spring in trial i. use 0.367 s for the value of the period. the mass of the suspended block is 0.400 kg. enter your answer in n/m with three significant figures.

Answer 1

The period of a spring as a function of the mass and the spring constant is given by:
 T = 2 * pi * root (m / k)
 We clear the value of k:
 root (m / k) = (T) / (2 * pi)
 m / k = ((T) / (2 * pi)) ^ 2
 k = m * ((2 * pi) / (T)) ^ 2
 Substituting the values:
 k = (0.400) * ((2 * (3.14)) / (0.367)) ^ 2
 k = 117.1243383
 three significant figures:
 k = 117 N / m
 Answer:
 the value of the spring constant is:
 k = 117 N / m