Question

Rationalise the denominator of 2√3 + 3√2/4√3 +√2

Answer 1

Answer:

$\frac{9+ 5\sqrt{6} }{23}$

Step-by-step explanation:

2√3 + 3√2 *   4√3 -√2

4√3 +√2          4√3 -√2

multiply by conjugate

2√3 + 3√2 *   4√3 -√2      =       18 +10√6   = 9 +5√6  

4√3 +√2          4√3 -√2                   46                   23

Answer 2

Answer:

Step-by-step explanation:

To rationalize the denominator, multiply the numerator and denominator by the conjugate of the denominator.

Conjugate of 4√3 + √2 is 4√3 - √2

(2√3 +3 √2)(4√3 - √2) = (2√3 * 4√3) - (2√3*√2) + (3√2*4√3) -(3√2*√2) {Use FOIL method}

= 8*3 - 2*√6+12√6 -3*2

= 24 -2√6 +12√6 - 6

= 24 - 6 + (-2+12)√6)

= 18 + 10√6

$\frac{2\sqrt{3}+3\sqrt{2} }{(4\sqrt{3}+\sqrt{2} }\\\\=\frac{(2\sqrt{3}+3\sqrt{2})(4\sqrt{3}-\sqrt{2}) }{(4\sqrt{3}+\sqrt{2} )(4\sqrt{3}-\sqrt{2} )}\\\\=\frac{18+10\sqrt{6} }{(4\sqrt{3})^{2}-(\sqrt{2})^{2} }\\\\=\frac{18+10\sqrt{6} }{48-2}\\\\=\frac{18+10\sqrt{6} }{46}\\\\\\=\frac{2(9+5\sqrt{6} )}{46}\\\\=\frac{9+5\sqrt{6} }{23}$