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trasher [3.6K]
3 years ago
8

A pie is cut into 12 equal slices. What is the angle of rotation about the center that will map a piece of pie to a piece that i

s two slices away from it?
Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
What? Hahahahahaggyvqywgvshwqvdhva scvsac
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A gym charges a one-time registration fee as well as a monthly fee. The cost of joining the gym for 4 months is $370, and the co
Anna007 [38]
x-\ registration\ fee\\
y-\ monthly\ fee\\\\
 \left \{ {{x+4y=370} \atop {x+6y=530\ \ |*(-1)}} \right. \\\\
 \left \{ {{x+4y=370} \atop {-x-6y=-530}} \right. \\+-----\\Addition\\\\
-2y=-160\ \ | divide\ by\ -2\\
y=80\\\\
x=370-4y=370-4*80=370-320=50\\\\
Registration\ fee\ is\ equal\ to\ 50\$\ and\ monthly\ fee\ is\ equal\ to\ 80\$.

8 0
3 years ago
Solve the problem using ELIMINATION<br> 20x + 2y = 18 10x + y = 9
sesenic [268]

Answer:

Infinitely many solutions.

Step-by-step explanation:

Multiply the second equation by -2, then add the equations together

(20x+2y=18)

−2(10x+y=9)  

20x+2y=18

−20x−2y=−18

Add these equations to eliminate x

0=0

Infinitely many solutions.

4 0
2 years ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
Hometown Donuts tracked how many of each type of donut were recently sold.
ziro4ka [17]

Answer:

4.62%

Step-by-Step Explanation:

Ask yourself: "3 is what percent of 65?" and solve.

Percentage solution with steps:

Step 1: We make the assumption that 65 is 100% since it is our output value.

Step 2: We next represent the value we seek with <em>x</em>.

Step 3: From step 1, it follows that 100%=65.

Step 4: In the same vein, x%=3.

Step 5: This gives us a pair of simple equations:

100%=65(1)

x%=3(2)

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

100% / x% =65 / 3

Step 7: Taking the inverse (or reciprocal) of both sides yields

x% / 100% =3 / 65

---> x = 4.62%

Therefore, 3 is 4.62% of 65.

3 0
2 years ago
The civil war had 6,020 people visit in 4 days. how many people visited each day
tatiyna
During the civil war, 1505 visited the war
5 0
3 years ago
Read 2 more answers
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