Answer:
(c)
"The given statement is true, by definition of length of a vector
,
"
Step-by-step explanation:
(a) 
That is completely correct Remember that if
then

Therefore the correct answer would be (c).
"The given statement is true, by definition of length of a vector
,
"
Answer:
no it's not because is not
Answer:
1. x = 16
2. x = 17
Step-by-step explanation:
1. The sum of the exterior angles of any polygon is 360 degrees. So, to find x, we can add up all of the angle measures and set them equal to 360, then solve for x:
46 + 93 + 47 + 4x + 62 + 3x = 360
Combine like terms:
248 + 7x = 360
Subtract 248 from both sides of the equation to isolate 7x:
7x = 112
Divide both sides by 7 to find the value of x:
x = 16
2. The sum of the interior angles for a 5-sided polygon is 540 degrees. So, to find x, we can add up all of the angle measures and set them equal to 540, and then solve for x:
5x + 139 + 9x + 71 + 92 = 540
Combine like terms:
14x + 302 = 540
Subtract 302 from both sides to isolate the 14x:
14x = 238
Divide both sides by 14 to find the value of x:
x = 17
I hope this helps :)
Answer:
Part 1) m∠1 =(1/2)[arc SP+arc QR]
Part 2) 
Part 3) PQ=PR
Part 4) m∠QPT=(1/2)[arc QT-arc QS]
Step-by-step explanation:
Part 1)
we know that
The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.
we have
m∠1 -----> is the inner angle
The arcs that comprise it and its opposite are arc SP and arc QR
so
m∠1 =(1/2)[arc SP+arc QR]
Part 2)
we know that
The <u>Intersecting Secant-Tangent Theorem,</u> states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.
so
In this problem we have that

Part 3)
we know that
The <u>Tangent-Tangent Theorem</u> states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments
so
In this problem
PQ=PR
Part 4)
we know that
The measurement of the outer angle is the semi-difference of the arcs it encompasses.
In this problem
m∠QPT -----> is the outer angle
The arcs that it encompasses are arc QT and arc QS
therefore
m∠QPT=(1/2)[arc QT-arc QS]
Solve for the first variable in one of the equations, then substitute the result into the other equation.
a
=
−
2
,
b
=
5
a
=
-
2
,
b
=
5
T