Step-by-step explanation:
H0: u = 150
H1: u ≠ 150
Total sum = 15933.24
N = 100
Mean = 15933.24/100
= 159.3324
σ² = 25954.03 - (159.3324)²/100
σ² = 556.213
σ = √556.213
σ = 23.8162
Testing hypothesis
t = (bar x - u)/ σ/√n
= 159.3324-150/23.8162/√100
= 3.91
We will have a p value of 0.02
0.0002 < 0.01
We reject null hypothesis at 1% level of significance
C. Mean = 159.3324
Se= 2.3936
Df = 100-1 = 99
Critical value at 0.01 = +-2.626
T = x-u/s.e
= -2.626 =( x -150)/2.3936
When we cross multiply and solve this
X = 143.714 for the lower tail
2.626 = (x-159)/2.3936
= 156.286 for upper tail.
We therefore reject H0 at
Bar X <= 143.71
Bar X >= 156.286
At 10%
Critical t = 1.660
-1.660 = (x - 150)/2.3936
Solving this ,
X =146.02 at the lower tail
1.660 = (x-150)/2.3936
X = 153.97
We reject H0 at
X<= 146.03
X>=153.97
Y= (3/x) - 4. You switch the X and Y and then get the Y by itself
Answer:
Tom is incorrect.
Step-by-step explanation:
A square by definition implies that all sides of the square are the same measurements. In the case of finding the area, A = s². Tom, however, solved it as A = 2s.
In this case:
Area of square = s² = 11² = 121 ft²
121 ft² is the correct measurement.
~
The answer to your problem is 69
Answer:
The nursery has a fixed rate and another variable.
The fixed is a total of 3 dollars. The variable changes depending on the delay time when picking up a child.
In this case the child is Albin, who presents the following equation:
10.50 = 0.50 * a + 3
Therefore, it would be the minutes for late pickup of Albin.