No solution for this question
Answer:
1.25*12=15
Step-by-step explanation:
probability that a dessert sold at a certain cafe contains chocolate is 86%.
The probability that a dessert containing chocolate also contains nuts is 30%.
Find the probability that a dessert chosen at random contains nuts given that it contains chocolate
P(nuts given chocolate) = .30/.86 = .349 or 34
Answer:
5
6
÷
1
6
=
5
6
×
6
1
=
5 × 6
6 × 1
=
30
6
=
30 ÷ 6
6 ÷ 6
= 5
the awnser would be 5
Step-by-step explanation:
10 5's go into 55 and
1 10 goes into 11
The answers I gave are only if you want them in 10's
