9(2k+3)+2=11 (k-y)
k=-11/7 y+ -29/7
I'm pretty sure it would be <span>x - y + 1 = 0 because if you plug in one of the coordinates into each equation, this is the only one that works.
</span><span>y - x + 1 = 0
2 - 1 + 1 = 0
2 = 0 not correct
</span><span>x - y + 1 = 0
1 - 2 + 1 = 0
0 = 0 correct
</span><span>-x - y + 1 = 0
-1 - 2 + 1 = 0
-2 = 0 not correct
</span>
Approximately there are some of these on the we
Answer: Area of square PQRS is 81cm^2 and of ABCD is 25cm^2
You know its a square. Which means all the sides are equal and same length. If you dont know what's a square then here is the definition:
Square is a plane figure with four equal sides and four right (90°) angles.
So now we know both of are squares, in case of the first square, PQRS, one side length is already given which is PQ=9cm. Now one side is 9cm which means all the sides are 9cm's (PQ=9cm, QR=9cm, RS=9cm,SP=9cm). So to find area just multiply them:
9cm * 9cm = 81cm^2
Now you found the area of the first square. So for the second square, ABCD, one side length is 5 cm so all the rest three sides are also 5 cm. Again, multiply them in order to find the area:
5cm * 5cm = 25cm^2
So square PQRS is 81cm^2 to that of square ABCD is 25cm^2
CAUTIONS: IT IS NOT THAT HARD YA KNOW
By the way, hope it helps! ^^
Answer:
0.000000014
Step-by-step explanation:
1.4 × 
= 
= 0.000000014
