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Tomtit [17]
3 years ago
14

HELP ME ASAP!!! A cargo plane left Los Angeles seven hours before an Air Force plane. The planes flew in opposite directions. Th

e Air Force plane flew at 325 mph for two hours. After this time the planes were 5150 mi. apart. Find the cargo plane's speed.
Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

The cargo plane's speed was 500 mph.

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A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t
Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be F=L+2W.

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

LW=80,000...(1)

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be C=20L+5(2W)\Rightarrow 20L+10W.

From equation (1), we will get:

L=\frac{80,000}{W}

Upon substituting this value in cost equation, we will get:

C=20(\frac{80,000}{W})+10W

C=\frac{1600,000}{W}+10W

C=1600,000W^{-1}+10W

To minimize the cost, we need to find critical points of the the derivative of cost function as:

C'=-1600,000W^{-2}+10

-1600,000W^{-2}+10=0

-1600,000W^{-2}=-10

-\frac{1600,000}{W^2}=-10

-10W^2=-1,600,000

W^2=160,000

\sqrt{W^2}=\pm\sqrt{160,000}  

W=\pm 400

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

C''=-2(-1600,000)W^{-3}

C''=3200,000W^{-3}

C''=\frac{3200,000}{W^3}

Now, we will substitute W=400 in 2nd derivative as:

C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05

Since 2nd derivative is positive at W=400, therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting W=400 in L=\frac{80,000}{W}, we will get:

L=\frac{80,000}{400}\\\\L=200

Therefore, the side parallel to the river will be 200 feet.

4 0
3 years ago
Plz help me answer the whole page
dangina [55]
#2 5.88 #3 6.510 #4 7.578 #5 9.835 #6 11.910 #7 3.72
8 0
3 years ago
(5•-3) - (4•-3) + -3 - (3•-3)
Dmitry_Shevchenko [17]
Use PEMDAS.

Parenthesis first.

(-15)-(-12)+3-(-9)

Next multiply,

(-15)+12+3+9 (two negatives get you a positive)

Finally, add and subtract:
-15+24=9

You get 9 as your answer.

Hope this helps!
4 0
3 years ago
In the diagram, the measures of angle 3 and angle 6 are 50 degrees. The measure of angle 5 is 130 degrees. Are lines c and d par
Virty [35]

9514 1404 393

Answer:

  (c)  Yes, because angle 3 and angle 6 are congruent

Step-by-step explanation:

Angles 3 and 6 are "alternate interior" angles. When those angles are congruent, as these are, then the lines crossed by the transversal are parallel.

__

We expect angles 5 and 6 to be supplementary because they are a linear pair. That fact says nothing about the relationship of line d to line c.

7 0
3 years ago
Variable a is 4 more than variable b. Variable a is also 1 less than b. Which of the following pairs of equations best models th
Elis [28]
B=a+4 that is what the answer will be.
4 0
3 years ago
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