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creativ13 [48]
3 years ago
14

X+ (-2x) Answers pleaseeeee!!!

Mathematics
2 answers:
Rina8888 [55]3 years ago
8 0
4x thAt the answer your welcome
svp [43]3 years ago
7 0

Answer:

it is -2x2

Step-by-step explanation:

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To rent a certain meeting room, a college charges a reservation fee of 15 and an additional fee of 5 per hour. The chemistry clu
Igoryamba

Answer:

The possible numbers the chemistry club could rent the room is less than 6 hours(t<6)

Step-by-step explanation:

Reservation fee = 15

Additional fee of 5 per hour

If the chemistry club wants to spend less than 45 on renting the room, let the possible number of hours be t.

t = time

15 + 5t < 45

5t < 45 - 15

5t < 30

t < 30/5

t < 6 hours

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4 years ago
Please I need help I have no idea how to do this and it’s due soon!
Anon25 [30]
I do this but I don’t remember how
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4 years ago
HELP PLZ I HAVE 5 MIN PLZZ
just olya [345]
6+8+b is assuming because it’s asking for the total weight
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3 years ago
The acceleration of an object (in m/s^2) is given by the function a(t) = 9 sin(t). The initial velocity of the object is v(0) =
pentagon [3]

a) Acceleration is the derivative of velocity. By the fundamental theorem of calculus,

v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du

so that

v(t)=\left(-11\frac{\rm m}{\rm s}\right)+\int_0^t9\sin u\,\mathrm du

\boxed{v(t)=-\left(2+9\cos t)\right)\frac{\rm m}{\rm s}}

b) We get the displacement by integrating the velocity function like above. Assume the object starts at the origin, so that its initial position is s(0)=0\,\mathrm m. Then its displacement over the time interval [0, 3] is

s(0)+\displaystyle\int_0^3v(t)\,\mathrm dt=-\int_0^3(2+9\cos t)\,\mathrm dt=\boxed{-6-9\sin3}

c) The total distance traveled is the integral of the absolute value of the velocity function:

s(0)+\displaystyle\int_0^3|v(t)|\,\mathrm dt

v(t) for 0\le t and v(t)\ge0 for \cos^{-1}\left(-\frac29\right)\le t\le3, so we split the integral into two as

\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}-v(t)\,\mathrm dt+\int_{\cos^{-1}\left(-\frac29\right)}^3v(t)\,\mathrm dt

=\displaystyle\int_0^{\cos^{-1}\left(-\frac29\right)}(2+9\cos t)\,\mathrm dt-\int_{\cos^{-1}\left(-\frac29\right)}^3(2+9\cos t)\,\mathrm dt

\displaystyle=\boxed{2\sqrt{77}-6+4\cos^{-1}\left(-\frac29\right)-9\sin3}

4 0
3 years ago
For the past two years Lynda Santana has recorded the costs of operating her car. They total $1,600 (fixed costs) and $2,134 (va
zmey [24]
Add the cost and divide by how many miles she drove:
1,600 + 2,134 / 1,400 =
3,734 / 1,400 = 2.66 (rounded to nearest decimal point)
So, Lynda paid roughly 2.66 per mile.
6 0
3 years ago
Read 2 more answers
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