[Given]
{ x + y = 6
{ x = y + 4
[Plug-in our x value & solve]
[Given] x + y = 6
[ Plug-in] (y + 4) + y = 6
[Distribute] y + 4 + y = 6
[Combine like terms] 2y + 4 = 6
[Subtract 4 from both sides] 2y = 2
[Divide both sides by 2] y = 1
[Answer]
Third option - (5, 1)
-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
★ Also please leave the rating you think I deserve (It helps other users as well as myself)
- Heather
Answer:
<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)
Step-by-step explanation:
To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:
Extended Rotation Rules
- 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
- 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
- 180°-rotation >> (x, y) → (-x, -y)
So, perform your rotation:
270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]
→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]
→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]
I am joyous to assist you anytime.
I'm sorry that I'm not in calculus, but hopefully I can help.
Personally, I would choose: D.) x; in the second equation ;
because it has easier numbers to figure out, you'll get it eventually...
29/4 hopes this help sorry if I’m wrong
