The complete question is
"Find the general solution of the given differential equation
y''-y=0, y1(t)=e^t , y2(t)=cosht
The function 
is the solution of the given differential equation.
The function y(t)=cosht is the solution of given differential equation.
<h3>What is a function?</h3>
The function is a type of relation, or rule, that maps one input to specific single output.
Given;
Given differential equations are,
y''-y = 0
So that,
Substitute values in the given differential equation.
Therefore, the function is the solution of the given differential equation.
Another function;
So that,
Hence, function y(t)=cosht is solution of given differential equation.
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These are fractions? Like 13/20 and 7/10? Is so the symbol would be 13/20 < 7/10 because 7/10 is a higher fraction than 13/20
Answer:
25 students
Step-by-step explanation:
What we need to do here is to do some tracing. We simply need to go to the point on the concert band where we have the value 35.
After sighting this value, we then make a tracing to the line of best fit. Then from this line of best fit, we trace the point on the matching band that correlated with the value 35.
If properly traced, we would arrive at a value of 25 on the marching band
If you keep simplifying it would end up to 4/21
Answer:
5x+3
Step-by-step explanation:
Rewrite the expression to 20x^2-3x-9/4x-3
Factor 20x^2+12x-15x-9/4x-3
Factor 4x*5x+3-3(5x+3)/4x-3
Factor (5x+3)*(4x-3)/4x-3
Solution then becomes 5x+3 as stated above
