Answer:
es verdad pero 3 nomas puede ser dividido por 3 o 1
Step-by-step explanation:
Answer:
Step-by-step explanation:
You can drag in the first empty box ∡3 and get ∡2≅∡3.
In the second box you can drag '' definition of angle bisector ''.
In the third empy box you can drag ∡1 and get ∡1≅∡3.
At last empy box you can drag ''transitive property of congruence''
Good luck!!!
Answer:
it’s g ! i just turned it in and it’s g :)
The poopulation exponential model is given by

Where, P(t) is the population after year t; Po is the initial population, t is the number of years from the starting year; k is the groth constant.
Given that the population in 1750 is 790 and the population in 1800 is 970, we obtain the population exponential equation as follows:

Thus, the exponential equation using the 1750 and the 1800 population values is

The population of 1900 using the 1750 and the 1800 population values is given by

The population of 1950 using the 1750 and the 1800 population values is given by

From the table, it can be seen that the actual figure is greater than the exponential model values.