4 years ago

What is the value of f(-3)

Mathematics

1 answer:

Oduvanchick [21]4 years ago

3 0

Answer:

Answer is(-3,4)

Step-by-step explanation:

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Answer:

A sample size of 21 is needed.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

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Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

Using an estimated standard deviation of $11,605

This means that $\sigma = 11605$

What sample size do you need to have a margin of error equal to $5000 with 95% confidence

A sample size of n is needed. n is found when M = 5000. So

$M = z\frac{\sigma}{\sqrt{n}}$

$5000 = 1.96\frac{11605}{\sqrt{n}}$

$5000\sqrt{n} = 1.96*11605$

$\sqrt{n} = \frac{1.96*11605}{5000}$

$(\sqrt{n})^2 = (\frac{1.96*11605}{5000})^2$

$n = 20.69$

Rounding up,

A sample size of 21 is needed.

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