Answer:
-6
Step-by-step explanation:
Given that :
we are to evaluate the Riemann sum for 
from 2 ≤ x ≤ 14
where the endpoints are included with six subintervals, taking the sample points to be the left endpoints.
The Riemann sum can be computed as follows:
where:
a = 2
b =14
n = 6
∴
Hence;
Here, we are using left end-points, then:
Replacing it into Riemann equation;
Estimating the integrals, we have :
= 6n - n(n+1)
replacing thevalue of n = 6 (i.e the sub interval number), we have:
= 6(6) - 6(6+1)
= 36 - 36 -6
= -6
When two balanced dice are rolled, the sum of the dice can be 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, or 12, giving 11 possibilities. th
RUDIKE [14]
False.
There are 36 possible outcomes, corresponding to numbers 1-6 independently appearing on each of the dice. Only one of those outcomes is double-sixes, resulting in a sum of 12. The probability that the sum is 12 is 1/36.
In short, the 11 outcomes listed in your problem statement are not equally-likely.
Answer: -6
Multiply 3 by -2 first =-6 inside brackets
Original 6 inside brackets plus -6 from performing multiplication problem inside the brackets equals 0, so you now have 0 minus the original -6 which equals -6 overall
Step-by-step explanation:
Answer:
4x-8
Step-by-step explanation:
y=-x2+6x-8
y=4x-8
Answer:
5/12
7/12
125/36 = 3,47%
50/11 = 4,54%
Step-by-step explanation:
Probability a black sock is selected when a person chooses 1 sock = 5/12
Probability a white or brown sock is selected when a person chooses 1 sock =
7/12
Probability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are replace = (4/12 * 5/12 * 3/12)*100 =125/36 = 3,47%
Pobability a person chooses 3 socks and selects a white first, a black second, and a brown last if the socks are NOT replace = (4/12 * 5/11 * 3/ 10)*100 = 50/11 = 4,54%
