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Ivahew [28]
3 years ago
5

Nina is 10 years younger than Deepak. Deepak is 3 times as old an Nina. Which system of equations can be used to find d, Deepak’

s age, and n, Nina’s age?

Mathematics
2 answers:
andre [41]3 years ago
8 0
The first choice is the correct answer. 
pickupchik [31]3 years ago
5 0

Answer:

A:d = n + 10

d = 3n is correct on E2020

Hope this helps

(please mark me as brainyest)

Step-by-step explanation:

I just took the test and this was right.

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The number of hours, h, that Mr. Hampton works varies directly with the number of tasks, t, he has to perform. If he has 6 tasks
olga2289 [7]

i think its 2.5 because 15/6= 2.5 so 2.5t=h and the equation is kt=h so 2.5 makes the most sense.

I hope this helps

4 0
2 years ago
Find the surface area of a square prism with a side measure of 15
Phoenix [80]
Since the length is 15, and the width would be 15, you need to first do 15 x 15.

15 x 15 = 225


Multiply the 6 faces.

225x6

Your final answer would be 1,350.
7 0
3 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
A special deck of cards has ten cards. Four are green (G), four are blue (B), and two are red (R). When a card is picked, the co
a_sh-v [17]

Answer:

{GT, GH, BT, BH, RT, RH};

1 /5;

Mutually exclusive ;

Not mutually exclusive.

Step-by-step explanation:

Given :

Green cards, G = 4

Blue cards, B = 4

Red cards, R = 2

For a coin toss :

{H, T}

A card is picked, then a coin is tossed :

Sample space :

{GT, GH, BT, BH, RT, RH}

2.) probability of picking a green card, then probability of landing a head on a coin toss

P(A) = number of required outcome / Total possible outcomes

P(A) = P(green card) * P(Head)

P(A) = (4 / 10) * (1/2)

P(A) = 4 /20

P(A) = 1/5

C.)

Both A and B are mutually exclusive, since both event A and event B cannot occur together, since both red and green cannot be picked during a single pick, this either a red is picked or green is picked, then they are A and B are mutually exclusive.

D.) Event A and C are not mutually exclusive, picking a green card, event A and picking a red or blue card, event B. Both event can happen simultaneously, hence, event A and B are not mutually exclusive.

6 0
3 years ago
Please help me with this question.
padilas [110]
It would be: = 56 1/4 % = 225/4% = 225/4/100 = 225/400 = 9/16

In short, Your Answer would be 9/16

Hope this helps!
6 0
3 years ago
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