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Ivahew [28]
4 years ago
5

Nina is 10 years younger than Deepak. Deepak is 3 times as old an Nina. Which system of equations can be used to find d, Deepak’

s age, and n, Nina’s age?

Mathematics
2 answers:
andre [41]4 years ago
8 0
The first choice is the correct answer. 
pickupchik [31]4 years ago
5 0

Answer:

A:d = n + 10

d = 3n is correct on E2020

Hope this helps

(please mark me as brainyest)

Step-by-step explanation:

I just took the test and this was right.

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Can you solve the system of equation using substitution y=x+8 <br> X+y=2
Vsevolod [243]
X + y = 2
Substitute x + 8 into y
x + x + 8 = 2
2x + 8 =2
(Subtract 8 from both sides)
2x = -6
(Divide both sides by 2)
x = -3

Subsitute x = -3 into either equation to find y
x + y = 2
-3 + y = 2
(Add 3 to both sides)
y = 2 + 3
y = 5

Or y can be solved for using:
y = x + 8
y = -3 + 8
y = 5
8 0
4 years ago
The area of the right triangle shown is 24 square feet. Which equations can be used to find the lengths of the legs of the trian
Yuri [45]
Not sure, but the areas of a triangle is BH/2 so the dimensions should be 8 and 6 then 10.
8 x 6 = 48
48/2 = 24
Maybe that can help with the equation
4 0
4 years ago
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How do you solve<br> -.8x + 40 - 8x - 35
makvit [3.9K]

Answer:

-16x + 5

Step-by-step explanation:

-8x + 40 -8x - 35

Collect like terms

-8x - 8x + 40 - 35

= - 16x + 5  or 5 - 16x

I hope this was helpful, Please mark as brainliest

6 0
3 years ago
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How do find volume of the triangular pyramid, I’m so confused I need the formula as well ASAP,!!,, please thanks so much
lidiya [134]

Answer:

5100

Step-by-step explanation:

20 x 17 x 15 = 5100. hope this helps you!!!

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6 0
2 years ago
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From a practice assignment:<br>solve the following differential equation given initial conditions ​
hodyreva [135]

If y' = e^y \sin(x) and y(-\pi)=0, separate variables in the differential equation to get

e^{-y} \, dy = \sin(x) \, dx

Integrate both sides:

\displaystyle \int e^{-y} \, dy = \int \sin(x) \, dx \implies -e^{-y} = -\cos(x) + C

Use the initial condition to solve for C :

-e^{-0} = -\cos(-\pi) + C \implies -1 = 1 + C \implies C = -2

Then the particular solution to the initial value problem is

-e^{-y} = -\cos(x) - 2 \implies e^{-y} = \cos(x) + 2

(A)

4 0
2 years ago
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