Question

The map of a biking trail is drawn on a coordinate grid.

Answer 1

The distance from (-2,1) to (6,1) is 8 units

The distance from (6,1) to (6,-3) is 4 units

The distance from (6,-3) to (9,-3) is 3 units

Now add 'em up: 8 + 4 + 3 = 15

The length of the biking trail is 15 units long!

Hope that helps!

Answer 2

Answer:

B. L=15 units

Step-by-step explanation:

We have four points:

P(-2,1)

Q(6,1)

R(6,-3)

S(9,-3)

If you have two points $A=(x_{1},y_{1}) , B=(x_{2},y_{2})$ the distance between those points is  the length of the segment that separates them. And the formula of that distance is:

$d(A,B)=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Then we have to calculate:

1. The distance between P and Q:

$d(P,Q)=\sqrt{(6-(-2))^2+(1-1)^2}=\sqrt{8^2}=8$

2. The distance between Q and R:

$d(Q,R)=\sqrt{(6-6)^2+(-3-1)^2}=\sqrt{(-4)^2}=4$

3. The distance between R and S:

$d(R,S)=\sqrt{(9-6)^2+(-3-(-3))^2}=\sqrt{(3)^2}=3$

Then the total length of the biking trail is:

$L=d(P,Q)+d(Q,R)+d(R,S)\\L=8+4+3\\L=15 units$

The answer is:

B. L=15 units