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MaRussiya [10]
3 years ago
12

Determine the median -2,-3,8,12,1,14

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

4.5 would be the median.

Putting these numbers into order from least to greatest, the middle number wouldn't be one number, but two. This means you have to add those two numbers together and divide it by two, giving you 4.5. Hope this helped, thanks for reading!

viva [34]3 years ago
8 0

Answer:


Step-by-step explanation:

put numbers in order least to greatest

-3, -2, 1, 8, 12, 14

find the number(s) in the middle

<em>-3, -2, </em>1, 8, <em>12, 14</em>

the median is between 1 and 8

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Answer:  x = 37

Explanation:

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3 years ago
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Which point is the midpoint of segment AB?
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Point X is the midpoint
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3 years ago
What is the value of the expression below when x<br> 3 and y = 8?<br> 6x + 10y
suter [353]

Answer:

98

Step-by-step explanation:

So we have the expression:

6x+10y

And we want to evaluate it when x is 3 and y is 8.

So, substitute:

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Multiply:

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7 0
3 years ago
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A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The
TiliK225 [7]

Correct question:

A food company sells salmon to various customers. The mean weight of the salmon is 44 lb with a standard deviation of 3 lbs. The company ships them to restaurants in boxes of 9 ​salmon, to grocery stores in cartons of 16 ​salmon, and to discount outlet stores in pallets of 64 salmon. To forecast​ costs, the shipping department needs to estimate the standard deviation of the mean weight of the salmon in each type of shipment. Complete parts​ (a) and​ (b) below.

a. Find the standard deviations of the mean weight of the salmon in each type of shipment.

b. The distribution of the salmon weights turns out to be skewed to the high end. Would the distribution of shipping weights be better characterized by a Normal model for the boxes or pallets?

Answer:

Given:

Mean, u = 44

Sd = 3

The company ships in boxes of 9, cartons of 16 and pallets of 64.

a) For the standard deviations of the mean weight of the salmon in each type of shipment, lets use the formula: \frac{s.d}{\sqrt{u}}

i) For the standard deviation of the mean weight of salmon in boxes of 9, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{9}}

= \frac{3}{3} = 1

The standard deviation = 1

ii) For the standard deviation of the mean weight of salmon in cartons of 16, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{16}}

= \frac{3}{4} = 0.75

Standard deviation = 0.75

iii) For the standard deviation of the mean weight of salmon in pellets of 64, we have:

\frac{s.d}{\sqrt{u}}

= \frac{3}{\sqrt{64}}

= \frac{3}{8} = 0.375

Standard deviation = 0.375

b) The distribution of shipping weights would be better characterized by a Normal model for the pallets, because regardless of the underlying distribution, the sampling distribution of the mean approaches the Normal model as the sample increases.

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