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Aleonysh [2.5K]
4 years ago
8

Suppose g(x)= f(x+2)-3. which statement best compares the graph of g(x) with the graph of f(x)

Mathematics
1 answer:
ycow [4]4 years ago
3 0
What are the statements?
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Find the values of x and y in the diagram.
SSSSS [86.1K]

Answer:

x = 15

y = 10

Step-by-step explanation:

ΔTUR is a 60°-60°-60° triangle because all angles are equal and  180/3 is 60

therefore, the angle adjacent to ∡R is 120 because it forms a straight line (which measures 180 degrees)

that means that angles T and S (which are both 3y°) plus angle R equal 180 so you can set up this equation to find y:  120 +6y = 180

                                                                6y = 60

                                                                 y = 10

Because angles T and S are the same we know that TR and TS are also the same, so RT is 15

ΔTUR is equiangular which means it is also equilateral; so if RT is 15 then UT and UR are 15 also

If UT = 15, we can write this equation: x - 5 = 15 and find that x = 20

7 0
3 years ago
There are three colors of marbles in a bag: green, red, and blue.
Arlecino [84]

Answer:

1/3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
I'm not even sure how to do this.
Andrews [41]

Answer:

8π

Step-by-step explanation:

360° = 2πr = πd

120° = 1/3 * 360°

120° = 2/3πr = 1/3πd

If the radius r = 12:

arcAB = 2/3π * 12 = 8π

7 0
3 years ago
Read 2 more answers
Find the mean of the data set . If necessary,round to the nearest tenth .
Sindrei [870]

Answer:

c

Step-by-step explanation:

thats it

6 0
3 years ago
A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte
vodka [1.7K]

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

<u><em>Let </em></u>\mu<u><em> = mean Ohio scores.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, H_A : \mu < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean Ohio score = 20.8

            \sigma = population standard deviation = 3

            n = sample of Ohio = 500

So, <u><em>test statistics</em></u>  =  \frac{20.8-21.1}{\frac{3}{\sqrt{500}}}  

                              =  -2.24

The value of z test statistics is -2.24.

<em>Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test.</em><em> Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the mean Ohio score is below the national average.

4 0
4 years ago
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