So r is a number that when you add to t it will increase so its
T + r
In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.
To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9
To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36
Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.
P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9
Answer:
2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2 2
Answer:
337.406388 or 337 people
Step-by-step explanation:
To figure this out, use the compound interest (compounding number?) equation which is Amount = People(1 + rate)^time
So if you fill that out you get
A = 20,000(.96)^100
A = 20,000(0.0168703194)
A = 337.406388
Answer:
t=-3
Step-by-step explanation:
Divide 6 from -18
-18÷6=-3
t=-3
