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3 years ago

13

Consider the relation y = 5|x − 7| + 2. Which of the following best describes the minimum or maximum of this relation?

1 answer:

Mandarinka [93]3 years ago

6 0

Minimum at (7,2) ................

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What is the value of b in the equation 3b + 2(b − 1) = 8?<br><br> 2<br> 5<br> 8<br> 10

Zanzabum

3b+2(b-1) = 8 3b+2b-2 = 8 5b = 8+2 5b = 10 b = 2

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3 years ago

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X + y = 4 <br>y = 1<br>write in slope intercept form

Ne4ueva [31]

Answer:

this is so wrong so 76 89676

Step-by-step explanation:

wrong 95454

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3 years ago

Determine whether each expression is equivalent to 49^2t – 0.5.

vampirchik [111]

Answer:

None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

Find its equivalents

We start by expanding the given expression

$49^{(2t - 0.5)}$

Expand 49

$(7^2)^{(2t - 0.5)}$

$7^2^{(2t - 0.5)}$

Using laws of indices: $(a^m)^n = a^{mn}$

$7^{(2*2t - 2*0.5)}$

$7^{(4t - 1)}$

This implies that; each of the following options A,B and C must be equivalent to $49^{(2t - 0.5)}$ or alternatively, $7^{(4t - 1)}$

A. $\frac{7^{2t}}{49^{0.5}}$

Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

$\frac{(7 * 7)^{t}}{49^{0.5}}$

$\frac{49^{t}}{49^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{49^{t}}{49^{0.5}}$ becomes

$49^{t-0.5}}$

This is not equivalent to $49^{(2t - 0.5)}$

B. $\frac{49^{2t}}{7^{0.5}}$

Expand numerator

$\frac{(7*7)^{2t}}{7^{0.5}}$

$\frac{(7^2)^{2t}}{7^{0.5}}$

Using law of indices which states;

$(a^m)^n = a^{mn}$

Applying this law to the numerator; we have

$\frac{7^{2*2t}}{7^{0.5}}$

$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

$\frac{7^{4t}}{7^{0.5}}$ = $7^{4t - 0.5}$

This is also not equivalent to $49^{(2t - 0.5)}$

C. $7^{2t}\ *\ 49^{0.5}$

$7^{2t}\ *\ (7^2)^{0.5}$

$7^{2t}\ *\ 7^{2*0.5}$

$7^{2t}\ *\ 7^{1}$

Using law of indices which states;

$a^m*a^n = a^{m+n}$

$7^{2t+ 1}$

This is also not equivalent to $49^{(2t - 0.5)}$

6 0

4 years ago

16.2 Jumping Rope

slava [35]

Answer:

Percentage of Diego's time is 75%.

Step-by-step explanation:

Given : Jumping Rope hool held a jump-roping contest. Diego jumped rope for 20 minutes. A school held a jur Jada jumped rope for 15 minutes.

To find : What percentage of Diego's time is that?

Solution :

Diego jumped rope for 20 minutes.

Jada jumped rope for 15 minutes.

Percentage of Diego's time is given by,

$\text{Percentage change}=\frac{\text{Jada time}}{\text{Diego time}}\times 100$

$\text{Percentage change}=\frac{15}{20}\times 100$

$\text{Percentage change}=75\%$

Therefore, percentage of Diego's time is 75%.

7 0

3 years ago

Y=2x-6<br> slope? <br> y- intercept?

krek1111 [17]

Answer:

The slope is 2/1 and the y-intercept is -6.

Step-by-step explanation:

With the y=mx+b formula, m is the slope and b is the intercept.

4 0

3 years ago

Read 2 more answers