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Anettt [7]
3 years ago
10

PLEASE HELP ME!!!!!!!

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0
Monday $2000 Tuesday $1800 wendsday $ 1440 thursday $5670
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Use the quadratic formula to solve the equation <br> 25x^2-30x+25=0
Reika [66]

Answer: x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

Step-by-step explanation:

25x^2-30x+25=0

x_{1,\:2}=\frac{-\left(-30\right)\pm \sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}}{2\cdot \:25}

\sqrt{\left(-30\right)^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-4\cdot \:25\cdot \:25}

=\sqrt{30^2-2500}

=i\sqrt{2500-30^2}

=40i

x_{1,\:2}=\frac{-\left(-30\right)\pm \:40i}{2\cdot \:25}

x_1=\frac{-\left(-30\right)+40i}{2\cdot \:25},\:x_2=\frac{-\left(-30\right)-40i}{2\cdot \:25}

x=\frac{3}{5}+i\frac{4}{5},\:x=\frac{3}{5}-i\frac{4}{5}

8 0
3 years ago
A cube-shaped water tank having 6 ft side lengths is being filled with water. The bottom is solid metal but the sides of the tan
Mekhanik [1.2K]

Answer:

0.033 ft

Step-by-step explanation:

Let g = 32.2 ft/s2 and h be the maximum height that water can be filled before the sides shatter.

Pressure is distributed from 0 to maximum at the bottom like the following equation:

P = \rho gh

So the force generated by water pressure on the side of the tank is

F = PA = \rho ghs/2

where s = 6ft is the side length of the tank. This force cannot be larger than 200lb

\rho ghs/2 \leq 200

62.4*32.2*h*6/2 \leq 200

h \leq 0.033 ft

4 0
4 years ago
Three times a number x is at least -18
Ksivusya [100]
3x is greater than or equal to -18. You would divide each side by 3 to get x alone. Then You will get what x stands for. (x= -6)
4 0
3 years ago
What does 144inch board equals to ...
Sedbober [7]
24 foot board... I added a picture for the break down

4 0
3 years ago
Enter the x-coordinate of the solution to this system of equations
Kitty [74]

Answer:

equation 2into minus 3 into equation 1

8x+ 3y= -28

-3x-3y=18

----------------

5x=10

x =2

put value of y in equation 2

8 into 2+3y=-28

16+3y= -28

3y= -28+16

3y= -12

y= -4

5 0
3 years ago
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