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Ede4ka [16]
3 years ago
14

Solve for k. 9(3-2x)=2(10-8x)

Mathematics
1 answer:
GrogVix [38]3 years ago
3 0

Answer:

Step-by-step explanation:

9(3−2x)=2(10−8x)

Step 1: Simplify both sides of the equation.

9(3−2x)=2(10−8x)

(9)(3)+(9)(−2x)=(2)(10)+(2)(−8x)(Distribute)

27+−18x=20+−16x

−18x+27=−16x+20

Step 2: Add 16x to both sides.

−18x+27+16x=−16x+20+16x

−2x+27=20

Step 3: Subtract 27 from both sides.

−2x+27−27=20−27

−2x=−7

Step 4: Divide both sides by -2.

−2x −2  =  −7 /−2  

x= 7/ 2

Answer:

x= 7/ 2

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f

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Explanation:

If the zero is c, the factor is (x-c).

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−

1

3

.

f

(

x

)

=

(

x

+

3

)

(

3

x

+

1

)

(

x

−

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)

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50

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Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

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