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3 years ago

Solve for k. 9(3-2x)=2(10-8x)

Mathematics

1 answer:

GrogVix [38]3 years ago

3 0

Answer:

Step-by-step explanation:

9(3−2x)=2(10−8x)

Step 1: Simplify both sides of the equation.

9(3−2x)=2(10−8x)

(9)(3)+(9)(−2x)=(2)(10)+(2)(−8x)(Distribute)

27+−18x=20+−16x

−18x+27=−16x+20

Step 2: Add 16x to both sides.

−18x+27+16x=−16x+20+16x

−2x+27=20

Step 3: Subtract 27 from both sides.

−2x+27−27=20−27

−2x=−7

Step 4: Divide both sides by -2.

−2x −2 = −7 /−2

x= 7/ 2

Answer:

x= 7/ 2

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How many sides does a regular polygon have if its interior angles <br><br>A. 156<br>B. 162

Kruka [31]

I) 156 degrees
The exterior angle is 180-156
=24
The number of sides= $\frac{360}{24}$
The number of sides= 15 sides

ii) 162 degrees
The exterior angle= 180-162
=18
The number of sides= $\frac{360}{18}$
= 20 sides

4 0

3 years ago

Find the length of each arc. Round your answer to the nearest tenth

Anvisha [2.4K]

I think the answer is B

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2 years ago

One vegetable warehouse had 210 tons of potatoes, another one had 180 tons. 90 tons of potatoes were delivered to the first and

kow [346]

Answer:

The number of days in which the amount in warehouse #2 is 1.2 greater than warehouse #1 is 6 days.

Step-by-step explanation:

Let

x: number of days

y: amount of potatoes

We can express the amount of potatoes in each warehouse using linear equations:

Warehouse #1: $y_1 = 90x+210$

Warehouse #2: $y_2 = 120x+180$

We need to find the value of x when $1.2*y_{1} =y_{2}$

Substituting the expressions for y1 and y2 in $1.2*y_{1} =y_{2}$ :

$1.2*(90x+210) =120x+180$

Applying distributive law:

$108x+252 =120x+180$

Solving the equation by subtracting 108x and 180 on both sides:

$108x+252-108x-180 =120x+180-108x-180$

$252-180 =120x-108x$

$72 =12x$

Now we divide by 12 on both sides:

$\frac{72}{12} =\frac{12x}{12}\\6=x\\x=6$

Therefore, the number of days in which the amount in warehouse #2 is 1.2 greater than warehouse #1 is 6 days.

4 0

3 years ago

Find the point-slope equation for the line that passes through the points (5, 35) and (-6, -31). Use the first point in your equ

AleksandrR [38]

Answer:

Maya, this is such a common question on here, so i'm very interested in what's difficult about this problem for you. Please comment about this. Below is the answer and how to find it.

Step-by-step explanation:

point P1 (5,35) in the form (x1,y1)

point P2(-6,-31) in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

m = (-31-35) / (-6-5)

m = -66 / -11

they made it easy for you , huh

m = 6

use point / slope fomula, y-y1 = m(x-x1) and plug in one point, either would work, since i've already labeled it with point P1, let's use that point

y-35 = 6(x-5)

y-35 = 6x-30

y = 6x - 30 + 35

y = 6x + 5

Maya, this really is a very common question on here, I really am curious about what's tricky in the problem for you and many many others. please let me know in comments section, thanks MMM

8 0

1 year ago

Read 2 more answers

The annual salaries of employees in a large company are approximately normally distributed with a mean of $50,000 and a standard

Anna35 [415]

Answer:

a) 30.85% of people earn less than $40,000

b) 37.21% of people earn between $45,000 and $65,000.

c) 15.87% of people earn more than $70,000

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 50000, \sigma = 20000$