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IrinaVladis [17]
2 years ago
14

n an after school program, students must choose to either play on the playground or read a book silently. On one cloudy day, 70%

of the students chose to play on the playground, and the rest chose read a book silently. 60% of the students who went to the playground are boys, and 20% who stayed inside to read a book are boys. If a student is randomly selected on this day, what is the probability that the student is a girl?
Mathematics
1 answer:
uranmaximum [27]2 years ago
4 0
20% b/c
70% playground - 60% boys= 10%girls
100% total-70% playground = 30% inside
30% inside-20% boys= 10%girls
10%girls +10% girls=20%girls
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4x/5 - x = x/10 -9/2
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Hopefully this help you !!

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3 years ago
estimate a 15% tip on a dinner bill of $49.75 by rounding first bill amount to the nearest ten dollars
AlladinOne [14]

Answer:

60.00

Step-by-step explanation:

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7 0
3 years ago
What is the midpoint of the segment shown below (-8,-7) (-7,-8)
svetlana [45]
Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)

In this case, the points would be: (-8,-7) and (-7,-8); therefore:
M=((-8-7)/2 , (-7-8)/2)=(-15/2,-15/2)

Answer: C.)  (-15/2 , -15,2)
6 0
3 years ago
Help?<br><br> a) 2/10 + 8/100<br> b) 13/100 + 4/10<br> c) 6/10 + 39/100<br> D) 70/100 + 3/10
Leni [432]

\green{––––––––––––––––––––––––––––––}

\huge\red{\boxed{\tt{{«ANSWER»}}}}

  • A) 2/10 + 8/100 = <u>0</u><u>.</u><u>2</u><u>8</u>
  • B) 13/100 + 4/10 = <u>0</u><u>.</u><u>5</u><u>3</u>
  • C) 6/10 + 39/100 = <u>0</u><u>.</u><u>9</u><u>9</u>
  • D) 70/100 + 3/10 = <u>1</u>

<u>\green{––––––––––––––––––––––––––––––}</u>

<em><u>#</u></em><em><u>carry </u></em><em><u>on </u></em><em><u>learning </u></em><u><</u><u>3</u>

5 0
2 years ago
Draw and write to explain how these two problems are different 35-15=. And 43-26=.
Rashid [163]
35-15 is 20. and 43-26 is 17. These two are different because you are regrouping in the 2d problem, as in the first, you just subtract. 
3 0
2 years ago
Read 2 more answers
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