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Artyom0805 [142]
3 years ago
7

Which ordered pair is in the solution set of 2 x − 5 y ≥ 10

Mathematics
1 answer:
frosja888 [35]3 years ago
3 0
(0,5) is the answer
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If an exterior angle of a regular polygon is 21.2° how many sides does the polygon have?
rosijanka [135]
\bf \textit{sum of all exterior angles in a polygon}\\\\
n\theta =360\quad 
\begin{cases}
n=\textit{number of sides}\\
\theta =\textit{angle in degrees}\\
----------\\
\theta =21.2^o
\end{cases}\implies n21.2=360
\\\\\\
n=\cfrac{360}{21.2}\implies n\approx 16.981132\implies n\approx 17

the reason why the value is not an integer, is most likely because the 21.2<span>° is just an approximation.</span>
8 0
3 years ago
HELP PLEASE SIMPLIFY !!!
Lelechka [254]

Answer:

=x^{\frac{5}{6}}+2x^{\frac{7}{3}}

Step-by-step explanation:

x^{\frac{1}{3}}\left(x^{\frac{1}{2}}+2x^2\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=x^{\frac{1}{3}},\:b=x^{\frac{1}{2}},\:c=2x^2\\=x^{\frac{1}{3}}x^{\frac{1}{2}}+x^{\frac{1}{3}}\cdot \:2x^2\\=x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}\\\mathrm{Simplify}\:x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}:\quad x^{\frac{5}{6}}+2x^{\frac{7}{3}}\\x^{\frac{1}{3}}x^{\frac{1}{2}}+2x^2x^{\frac{1}{3}}\\x^{\frac{1}{3}}x^{\frac{1}{2}}=x^{\frac{5}{6}}

x^{\frac{1}{3}}x^{\frac{1}{2}}\\\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}\\x^{\frac{1}{3}}x^{\frac{1}{2}}=\:x^{\frac{1}{3}+\frac{1}{2}}\\=x^{\frac{1}{3}+\frac{1}{2}}\\\mathrm{Join}\:\frac{1}{3}+\frac{1}{2}:\quad \frac{5}{6}\\\frac{1}{3}+\frac{1}{2}\\\mathrm{Least\:Common\:Multiplier\:of\:}3,\:2:\quad 6\\Adjust\:Fractions\:based\:on\:the\:LCM\\=\frac{2}{6}+\frac{3}{6}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\=\frac{2+3}{6}\\\mathrm{Add\:the\:numbers:}\:2+3=5\\=\frac{5}{6}\\=x^{\frac{5}{6}}\\2x^2x^{\frac{1}{3}}=2x^{\frac{7}{3}}\\=x^{\frac{5}{6}}+2x^{\frac{7}{3}}

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3 years ago
Jaclyn used the slope formula to find the slope of the line through the points given in the table. In which step did Jaclyn make
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Answer: C. Jaclyn did not make an error. I just worked on this on e2020

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A certain 5-digit combination lock can be reset with a new combination. The lock uses numbers from 1 to 6. After a friend accide
daser333 [38]
The probability is (1/6)^5 power. Since the locks are independent of each other, you can multiply the probabilities together. There are 6 possible numbers for each lock and there are 5 locks. So the probability is (1/6)^5 power.<span />
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4 years ago
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