A polynomial function of least degree with integral coefficients that has the
given zeros 
Given
Given zeros are 3i, -1 and 0
complex zeros occurs in pairs. 3i is one of the zero
-3i is the other zero
So zeros are 3i, -3i, 0 and -1
Now we write the zeros in factor form
If 'a' is a zero then (x-a) is a factor
the factor form of given zeros
Now we multiply it to get the polynomial
polynomial function of least degree with integral coefficients that has the
given zeros
Learn more : brainly.com/question/7619478
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Answer:
f(x) = x³ +3x² -6x -18
Step-by-step explanation:
In order for there to be a root of √6, there must be a factor of (x-√6). In order for there to be rational coefficients, there needs to be another factor of (x+√6) in the minimal polynomial. Then the minimal polynomial with the required roots is ...
f(x) = (x +3)(x -√6)(x +√6) = (x +3)(x² -6)
f(x) = x³ +3x² -6x -18
Answer:
12 x 10 = 120
120 divided by 2 = 60
Formula of a triangle:
B(base) x H(height) x 1/2(basically dividing by 2)
Do you mean a_(n+1), worded a sub (n+1)?
If so yes. If the function of the sequence is getting smaller or more negative with each term.
<span>Break down every term into prime factors. ...Look for factors that appear in every single term to determine the GCF. ...Factor the GCF out from every term in front of parentheses, and leave the remnants inside the parentheses. ...<span>Multiply out to simplify each term. </span></span>
