Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer: (f + 2) (f + 8)
It's hard to explain, but I suggest you use the AC method. Hope this helps!
Answer:
2
Step-by-step explanation:
slope = difference of y/ difference of x
m = (9-5) / (4-2) = 4/2 = 2
Answer:
D) 81x²y¹⁰
Step-by-step explanation:
(9xy⁵)²
Because all of 9xy⁵ are in the parentheses, each component is raised to the 2nd degree.
(9)² = 81
(x)² = x²
(y⁵)² = y¹⁰ -- When you raise an exponent to another exponent, you multiply the exponents.
Now combine the components.
D) 81x²y¹⁰
