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Burka [1]
3 years ago
12

Which collaboration technology is becoming more and more popular within organizations because it provides a means for forming ad

hoc groups, networking and locating potential business allies?
a) Intranet
b) Wikis
c) VoIP
d) Social networking sites
e) Unified communications
Computers and Technology
1 answer:
Leona [35]3 years ago
8 0

Answer:

d) Social networking sites

Explanation:

-Intranet is a network that is created by an organization to share information, tools and different services inside the company.

-Wikis are websites used to share content and knowledge and different users can modify the information.

-VoIP is a technology that allows you to make calls over the internet.

-Social networking sites are online platforms that allow people to connect with organizations and other people, create communities online and share different types of information.

-Unified communications is a system that has different communication methods through a single application.

According to this, the collaboration technology that is becoming more and more popular within organizations because it provides a means for forming ad hoc groups, networking and locating potential business allies is social networking sites.

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Under which of the following conditions will evaluating this boolean expression
zzz [600]
1.) 
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>

<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>

<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>

<span>a.) (i <= n) || (i >= n) </span>

<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>

<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>

<span>This means that both of these terms are true. We substitute. </span>

<span>((i <= n) && true) || (((i >= n) && true)) </span>

<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>

<span>(i <= n) || (i >= n) </span>

<span>This is clearly always true. </span>
3 0
3 years ago
Arrange the code so that the numbers are swapped.
Ahat [919]
Rand.int(your_num , your_num
5 0
3 years ago
Create an array to hold the rainfall values. Create a 2nd parallel array (as a constant) to hold the abbreviated names of the mo
Zarrin [17]

Answer:

#include <stdio.h>

int main()

{

//variable declaration

int low, high;

float lowRain, highRain, total, avg;

 

//array declaration

float rainfall[13];

char monthName[13][10] = {"", "Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec"};

//get user input

for(int i=1; i<=12; i++)

{

printf("Enter the rainfall (in inches) for %s: ", monthName[i]);

scanf("%f", &rainfall[i]);

}

 

//display the monthly rainfall

printf("\nThe rainfall that was entered was:\n");

for(int i = 1; i<=6; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 1; i<=6; i++)

printf("%.1f ", rainfall[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%s ", monthName[i]);

printf("\n");

for(int i = 7; i<=12; i++)

printf("%.1f ", rainfall[i]);

 

//variable initialization

low = 1;

high = 1;

lowRain = rainfall[1];

highRain = rainfall[1];

total = 0;

 

//calculate the lowest, highest and averaage rainfall

for(int i=1; i<=12; i++)

{

if(lowRain>rainfall[i])

{

lowRain = rainfall[i];

low = i;

}

if(highRain<rainfall[i])

{

highRain = rainfall[i];

high = i;

}

total = total + rainfall[i];

}

 

avg = total / 12;

 

//display the result

printf("\n\nThe total rain that fell was %.1f inches", total);

printf("\nThe average monthly rainfall was %.1f inches.", avg);

printf("\nThe lowest monthly rainfall was %.1f inches in %s.", rainfall[low], monthName[low]);

printf("\nThe highest monthly rainfall was %.1f inches in %s.", rainfall[high], monthName[high]);

return 0;

}

4 0
4 years ago
Risk of new technology is NOT evaluated by asking questions during which phase?
neonofarm [45]

Answer:

the answer is D

Explanation:

hope this helps :)

4 0
3 years ago
Two files named numbers1.txt and numbers2.txt both have an unknown number of lines, each line consisting of a single positive in
Reika [66]

Answer:

see explaination for program code

Explanation:

scalar_product = 0

li=[]

li2=[]

#reading numbers1.txt and numbers2.txt intoli and li2 respectively

with open('numbers1.txt') as n1, open('numbers2.txt') as n2:

for line1 in n1:

li.append(int(line1))

for line2 in n2:

li2.append(int(line2))

#storing min list size into variable l

a=len(li)

b=len(li2)

if a<b:

l=a

else:

l=b

#calculating scalar product

for i in range(l):

scalar_product=scalar_product+li[i]*li2[i]

print("scalar product is",scalar_product)

6 0
3 years ago
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