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3 years ago

Which statement describes the cost to park as a unit price?

Mathematics

2 answers:

shepuryov [24]3 years ago

7 0

Answer:

the answer is c

i took the text

Step-by-step explanation:

Lana71 [14]3 years ago

4 0

The answer is C

hope this helps

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An ambulance has a mass of 5.44×105 ounces. Which unit of measurement is most appropriate to measure this mass? milligrams tons

ArbitrLikvidat [17]

Kilograms would be the answer

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3 years ago

Yesterday, Grace drove 2 1/8 miles. she used 1 1/4

prisoha [69]

Answer:

7/8

Step-by-step explanation:

3 0

3 years ago

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The base of a triangular prism is an isosceles right triangle with a hypotenuse of 72−−√ centimeters. The height of the prism is

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Surface area = lateral area + 2(area of base)

Lateral area = perimeter of base * height.

Because it is a isosceles right triangle, both sides are equal.

$x^{2} +x^{2}$ = 72

2 $x^{2}$ = 72. Divide both sides by 2

$x^{2}$ = 36. Square both sides.

x = 6.

So the perimeter of the base = 6 + 6 + $\sqrt{72}$ = 20.485281374239

Lateral area = 20.485281374239 * 7 = 143.397 $cm^{2}$

Area of base is (1/2)base * height.

(1/2)(6)(6) = 18

Using the surface area formula

surface area = 143.397 + 2(18) = 179.4 $cm^{3}$

4 0

3 years ago

What is the surface area of this design ?

Fed [463]

Answer:

384 8x8=64 64x2=128 128x3=384

Step-by-step explanation:

8 0

3 years ago

Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

3 years ago