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tankabanditka [31]
3 years ago
9

Which statement describes the cost to park as a unit price?

Mathematics
2 answers:
shepuryov [24]3 years ago
7 0

Answer:

the answer is c

i took the text

Step-by-step explanation:

Lana71 [14]3 years ago
4 0

The answer is C

hope this helps

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An ambulance has a mass of 5.44×105 ounces. Which unit of measurement is most appropriate to measure this mass? milligrams tons
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Kilograms would be the answer
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Yesterday, Grace drove 2 1/8 miles. she used 1 1/4
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7/8

Step-by-step explanation:

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The base of a triangular prism is an isosceles right triangle with a hypotenuse of 72−−√ centimeters. The height of the prism is
Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Surface area = lateral area + 2(area of base)

Lateral area = perimeter of base * height.

Because it is a isosceles right triangle, both sides are equal.

x^{2} +x^{2} = 72

2x^{2} = 72. Divide both sides by 2

x^{2} = 36.  Square both sides.

x = 6.

So the perimeter of the base = 6 + 6 +\sqrt{72} = 20.485281374239

Lateral area = 20.485281374239 * 7 = 143.397 cm^{2}

Area of base is (1/2)base * height.

(1/2)(6)(6) = 18

Using the surface area formula

surface area = 143.397 + 2(18) = 179.4 cm^{3}

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3 years ago
What is the surface area of this design ?
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Step-by-step explanation:

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3 years ago
Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4
gtnhenbr [62]

Answer:

Simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

Step-by-step explanation:

We need to simplify the expression (6^{-2})(3^{-3})(3*6)^4

Solving:

(6^{-2})(3^{-3})(3*6)^4

Applying exponent rule: a^{-m}=\frac{1}{a^m}

=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\

Factors of 18=2\times 3\times 3=2\times3^2

Factors of 6=2\times 3

Replacing terms with factors

=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\

Using exponent rule: (a^m)^n=a^{m\times n}

=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}

Using exponent rule: a^m.a^n=a^{m+n}

=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}

Now using exponent rule: \frac{a^m}{a^n}=a^{m-n}

=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108

So, simplifying the expression (6^{-2})(3^{-3})(3*6)^4 we get \mathbf{108}

7 0
3 years ago
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