The answer is 7/69.
There are 8 black-haired children among 24 children. The probability of <span>randomly selecting black haired children for the first time is:
P1 = 8/24 = 1/3
Now, there are 7 black-haired children left among 23 children. The probability of </span>randomly selecting black haired children for the second time is:
P2 = 7/23
Since we want both of these events to occur together, we will multiply their probabilities:
P = P1 * P2 = 1/3 * 7/23 = 7/69
Answer: D
Step-by-step explanation: A is not possible because the shape and the way it is drawn is nearly the same as the figure given. The shape of B is different from the given shape. C is a little too flat to be considered symmetrical to the figure. Which leaves only option D.
Hope this helped :D
Answer:
27
Step-by-step explanation
14 is the radius so multiply by pi to get 87.96
then turn 200 fee into in which is 2400in
and divide 2400 by 87.96
(a) If we let x be the number of miles and y be the total cost, the equation for relating the number of miles and the total cost would be,
y = 0.4x + 48
(b) If the rental cost is 60,
60 = 0.4x + 48
The value of x from the equation is 30.
(c) You may prepare the table of values by allowing x be any number and then solve for y until we arrive with an answer for y being equal to 60.
We can use the binomial theorem to find the probability that 0 out of the 15 samples will be defective, given that 20% are defective.
P(0/15) = (15C0) (0.2)^0 (1 - 0.2)^15 = (1)(1)(0.8)^15 = 0.0352
Then the probability that at least 1 is defective is equal to 1 - 0.0352 = 0.9648. This means there is a 96.48% chance that at least 1 of the 15 samples will be found defective. This is probably sufficient, though it depends on her significance level. If the usual 95% is used, then this is enough.
