Answer:
Alternate interior angles theorem
Step-by-step explanation:
Alternate interior angles theorem
Answer:x = -9, y = -7
Step-by-step explanation:
Equation 1) -x + 4y = -19
Equation 2) -3x + 3y = 6
Multiply ALL of equation 1 by 3 so that both equations include -3x in it.
1) 3(-x + 4y = -19)
Simplify.-3x + 12y = -57 → equation 3
Now, subtract equation 3 from equation 2.
-3x + 12y = -57
(-)-3x + 3y = 6
Simplify.
9y = -63
Divide both sides by 9.
9y ÷ 9 = -63 ÷ 9
Simplify.
y = -7
Now that we have the value for y, simply plug in -7 for y into equation 1.
1) -x + 4y = -19-x + 4(-7) = -19
Simplify.-x - 28 = -19
Add 28 to both sides of the equal sign.
-x - 28 + 28 = -19 + 28
Simplify.-x = 9
Divide both sides by -1.x = -9
Now we know that : x = -9, y = -7
To check our work, simply plug in -9 for x and -7 for y into equation 1.
1) -x + 4y = -19-(-9) + 4(-7) = -19
Simplify.
9 - 28 = -19-19 = -19
Therefore, x = -9, y = -7
Hope this helped! :)
Answer:
y = 1/5x + 8
Step-by-step explanation:
slope = (change in y)/(change in x)
Slope = (8 -10)/(0 -10)
Slope = -2/-10
Slope = 1/5
Use y = mx + b substitute m = 1/5 and (0, 8)
8 = 1/5(0) + b
8 = 0 + b
8 = b
The equation of the equation y = 1/5x +8
Answer:
The expression that represents the number of days until only 10% remains is T((d) 10 %) =100×.
Step-by-step explanation:
The equation for half life is of the form
A = A₀×.........................................................................(1)
Where
A = Final amount
A₀ = Initial amount
t = Time
h = Half life
For the equation T(d) = 100×2⁽⁻²⁾....................................(2)
We have by comparison with the equation for half life
2 ≡ and and the equation (2) can be written as
Percentage remaining after 2 half lives is
×100=100×
However if the half life of Technetium-99m is 6 hours then we have for one day
×100=100×
Therefore an expression that represents the number of days until only 10% remains is
×100=100× = 10 %
=
= ㏑ = ㏑()
= ×㏑ = ㏑()
= = 3.322
Therefore the expression for the number of days 10 % of Technetium-99m will be remaining is
T((d) 10 %) =100×