Question

A parking meter filled with \$4.50$4.50 in dimes and quarters contains twice as many dimes as quarters.(Note: 1 dime = \$.10$.10; 1 quarter = \$.25$.25)

Answer 1

Using a system of equations, it is found that the meter contains 20 dimes and 10 quarters.

System of equations:

For the system, the variables are:

• x is the number of dimes.

• y is the number of quarters.

A dime is worth $0.1 and a quarter is worth $0.25. In total, the parking meter is filled with $4.50, hence:

$0.1x + 0.25y = 4.5$

There are twice as many dimes as quarters, hence:

$x = 2y$

Then:

$0.1x + 0.25y = 4.5$

$0.1(2y) + 0.25y = 4.5$

$0.2y + 0.25y = 4.5$

$0.45y = 4.5$

$y = \frac{4.5}{0.45}$

$y = 10$

$x = 2y = 2(10) = 20$

There are 20 dimes and 10 quarters in the parking meter.

To learn more about system of equations, you can take a look at brainly.com/question/24342899