The answer is A. Always for perpendicular you flip the sign and the numbers
219864070186 - 277409297400 = -57545227214 x 780498 = -4.4913935e+16 - 1274806769367926946610431 = -1.2748068e+24 x 3.6614422e+21 = -4.6676314e+45 - 437913 = -4.6676314e+45 - 88878 = -4.6676314e+45
Ф = 500 , 5,000
5,000 / ∞ x ∞ x ∞ = 5,000^+++∞/ 68307147 = 0.00007319878^+++∞ - 917 - 974 - 9 - 19344381 = -19346280.9999^+++∞
-4.6676314e+45 -19346280.9999^+++∞ = -4.6676314e+45^+++∞
I believe that will be your answer.
I tried my best.
Answer:
The vertex of a quadratic equation corresponds to the point where the maximum or minimum value is located.
If the function has a positive leading coefficient, the vertex corresponds to the minimum value.
If it has a negative leading coefficient, the vertex corresponds to the maximum valuevalue
If the vertex is located at
(–2, 0)
The possibilities are
y = (x-2)^2
or,
y = - (x-2)^2
Since the problem tells us the answer, we adopt the positive values
Answer:
y = (x-2)^2
See attached picture
Hello,
Use the factoration
a^2 - b^2 = (a - b)(a + b)
Then,
x^2 - 81 = x^2 - 9^2
x^2 - 9^2 = ( x - 9).(x + 9)
Then,
Lim (x^2- 81) /(x+9)
= Lim (x -9)(x+9)/(x+9)
Simplity x + 9
Lim (x -9)
Now replace x = -9
Lim ( -9 -9)
Lim -18 = -18
_______________
The second method without using factorization would be to calculate the limit by the hospital rule.
Lim f(x)/g(x) = lim f(x)'/g(x)'
Where,
f(x)' and g(x)' are the derivates.
Let f(x) = x^2 -81
f(x)' = 2x + 0
f(x)' = 2x
Let g(x) = x +9
g(x)' = 1 + 0
g(x)' = 1
Then the Lim stay:
Lim (x^2 -81)/(x+9) = Lim 2x /1
Now replace x = -9
Lim 2×-9 = Lim -18
= -18
Answer:
5
Step-by-step explanation:
