Answer:
Sorry is there any more information i will then change answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
These come directly from my textbook, so I'm not sure if your teacher will accept this kind of work.
1. Angle construction:
Given an angle. construct an angle congruent to the given angle.
Given: Angle ABC
Construct: An angle congruent to angle ABC
Procedure:
1. Draw a ray. Label it ray RY.
2. Using B as center and any radius, draw an arc that intersects ray BA and ray BC. Label the points of intersection D and E, respectively.
3. Using R as center and the same radius as in Step 2, draw an arc intersecting ray RY. Label the arc XS, with S being the point where the arc intersects ray RY.
4. Using S as center and a radius equal to DE, draw an arc that intersects arc XS at a point Q.
5. Draw ray RQ.
Justification (for congruence): If you draw line segment DE and line segment QS, triangle DBE is congruent to triangle QRS (SSS postulate) Then angle QRS is congruent to angle ABC.
You can probably also Google videos if it's hard to imagine this. Sorry, construction is super hard to describe.
Hey there!
In order to find if a fraction would result in a repeating decimal, recall that a fraction is a division problem written vertically. All that you have to do is divide the numerator by the denominator. Also, remember that a repeating decimal will result in the same number after the decimal point as long as the calculator can handle.
3 ÷ 4 = 0.75
1 ÷ 9 = 0.11111111...
5 ÷ 11 = 0.45454545...
3 ÷ 0.42857143...
As you can see, two out of your four answer choices give you a repeating decimal. B gives you a repeated number of "1" while C gives you "45". D doesn't count since there is no pattern of repeated numbers that it follows.
Both B and C fall into the category of repeating decimal. If you're only able to choose one answer, I would ask your teacher, a parent, or a peer what they think.
Hope this helped you out! :-)
These calculations are based on the drawing of the file enclosed.
There are three right triangles.
From the big right triangle:
a^2 + b^2 = 25^2
From the small right triangle on the left side:
(25-x)^2 + 10^2 = a^2
From the small right triangle on the right side
x^2 +10^2 = b^2
=> (25-x)^2 + 10^2 + x^2 + 10^2 = a^2 + b^2
=> (25-x)^2 + 10^2 + x^2 + 10^2 = 25^2
=> 25^2 - 50x + x^2 + 10^2 + 10^2 = 25^2
=> x^2 -50x + 100 =0
Use the quadratic formular to find the roots:
x = 2.1 and x = 47.9
Distance from back: 25 - 2.1 = 22.9 ft
Answer: 22.9 ft
