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Natasha_Volkova [10]
2 years ago
15

The source or origin of a word is called its?​

Mathematics
2 answers:
Inessa05 [86]2 years ago
7 0

Answer:

Etymology

the study of the origin of words and the way in which their meanings have changed throughout history.

Step-by-step explanation:

inna [77]2 years ago
5 0

The answer is

Etymology.

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Considere a função de oferta como sendo y= 5x - 1/2 e a função de demanda como sendo y= -7x + 47/2 , onde x é a quantidade e y é
swat32

A) Temos que igualar isso a 2,50, que é o valor de y, ou seja, o valor do preço. Façamos isso, então, na função de demanda.

y = -7x + \frac{47}{2}

Substituir.

2,50 = - 7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x  = - \frac{47}{2} + 2,50

A fração 47/2 corresponde a 23,5. É mais interessante para nós, nesse caso, utilizar o valor decimal.

-7x  = - 23,5 + 2,50

Somar logo.

-7x = -21

Podemos multiplicar por -1 para tirar os sinais negativos.

7x = 21

Passar o x dividindo

x = \frac{21}{7}

Dividir

\boxed{x = 3}

Para um preço de R$ 2,50, a quantidade demandada é de 3 unidades.



B) Basta igualar as duas formulinhas.

5x - \frac{1}{2} = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x + 7x = \frac{47}{2} + \frac{1}{2}

Somar tudo. Como as frações têm o mesmo denominador, <u>nada de </u><u>mmc</u>! Basta somar os numeradores.

12x = \frac{48}{2}

Podemos dividir lá, olha:

12x = 24

Passar o x dividindo

x = \frac{24}{12}

Dividir

\boxed{x = 2}

O ponto de equilíbrio é o valor 2.



C) Basta, então, igualar as fórmulas da oferta e da demanda a 10.

Fórmula da oferta

10 = 5x - \frac{1}{2}

Passar o que é x de um lado e o que é número do outro lado.

5x = 10 - \frac{1}{2}

Se 1/2 = 0,5, dá pra resolver sem fazer mmc:

5x = 10 - 0,5

Subtrair

5x = 9,5

Passar dividindo

x = \frac{9,5}{5}

Dividir.

\boxed{x = 1,9}

Fórmula da demanda

10 = -7x + \frac{47}{2}

Passar o que é x de um lado e o que é número do outro lado.

-7x = \frac{47}{2} - 10

Divide 47/2, vai.

-7x = 23,5 - 10

Subtrair.

-7x = 13,5

Passar o 7 dividindo.

x = - \frac{13,5}{7}

Vamos dividir e transformar em decimal.

\boxed{x = -1,9285714285714285714285714285714}


Subtrair a oferta pela demanda.

x = 1,9 - (-1,9285714285714285714285714285714)

Subtrair.

\boxed{x = 3,8285714285714285714285714285714}

Arredondando, o preço será de R$ 3,83.

8 0
3 years ago
Use addition to solve the linear system of equations. Include all of your work in your final answer. \(\left\{ \right.\) 3x-y=6
ad-work [718]

Answer:

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

Step-by-step explanation:

We need to solve the linear system of equations.

3x-y=6 \\y=x-4

We can write second equation y=x-4  as: -x+y=-4

Let:

3x-y=6--eq(1)\\ -x+y=-4--eq(2)

Now, Adding equation 1 and 2

3x-y=6\\ -x+y=-4\\--------\\2x+0y=2\\2x=2\\x=\frac{2}{2}\\x=1

So, we get x = 1

Now, put value of x in second equation to find value of y:

y=x-4\\Put\:x=1\\y=1-4\\y=-3

So, we get y = -3

Solving the given linear system, we get x = 1 and y = -3.

The solution set is: (1,-3)

4 0
3 years ago
What is 2 and 3/4 divided by 1/4
Tanya [424]
2 3/4 divided by 1/4
is
2 3/4 multiplied by 4/1

which is (2+3/4)*4 = 2*4 + 3/4*4 = 8+3 =<em>11</em>
3 0
3 years ago
How do you simpllify x=41
HACTEHA [7]

Answer:

You have to figure out what x means

Step-by-step explanation:

bc i know math. a liitle bit and like to help.

6 0
3 years ago
(gh)^0 I'm very confused can you show me how to solve this
lana [24]

The expression is:

(9d^{10})^{-2}

Simplify the expression:

1. Multiply the exponent outside the parenthesis with every exponent inside the parenthesis,

\begin{gathered} (9d^{10})^{-2}=9^2d^{(-10)\times2} \\ (9d^{10})^{-2}=9^{-2}d^{-20} \end{gathered}

Since, exponents in negative form are express as fraction with 1 as numerator.

\begin{gathered} \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=9^{-2}d^{\mleft\{-20\mright\}} \\ \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=\frac{1}{9^2}\times d^{\mleft\{-20\mright\}} \\ \mleft(9d^{\mleft\{10\mright\}}\mright)^{\mleft\{-2\mright\}}=\frac{1}{81}^{}d^{\mleft\{-20\mright\}} \end{gathered}

Answer: 1/81d^(-20)

3 0
1 year ago
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