At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the
1 answer:
Answer:
4600
Step-by-step explanation:
We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.
We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.
30y=100(1380)
30y=138000
y=4600.
There are 4600 students who attend the university.
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Answer:
<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295, so I will take the car to Amy's shop</em>
<em>Point of intersection: (x,y) = (4,360)</em>
Explanation:
Part 1 )
Let x = number of hours worked
Let y = total cost to you
Determining where to take the car:
<em>Total Cost at Amy's shop is $280 which is less than the total cost at Mike's shop which is $295</em>
Mike's repair shop:
Service fee: $100
Per hour rate: $65
Let x is the number of hours worked on. Total cost will be equal to the service fee plus hourly charges. Charges per an hour are $65, so for x hours the charges will be 65x.
Therefore, total cost for Amy's repair shop can be written as:
y = 100 + 65x ------(1)
For 3 hours work: y = 100 + 65(3)
<em>Cost at Mike's, y = $100 + $195 = $295</em>
<em>Amy's repair shop: </em>
Service fee: $40
Per hour rate: $80
Charges per an hour are $40, so for x hours the charges will be 80x.
Therefore, total cost for Amy's repair shop can be written as:
y = 40 + 80x ------(2)
For 3 hours work: x = 3
y = 40 + 80(3)
<em>Cost at Amy's, y = $40 + $240 = $280</em>
<em>Part 2)</em>
<em>Find the point of intersection</em>
<em>Using elimination method:</em>
<em>y = 100 + 65 x ------1</em>
<em>y = 40 + 80x ------2</em>
<em>As the y coefficients are equal we will subtract eq1 from eq2</em>
<em>y - y = 40 + 80x - 100 - 65x</em>
<em>0 = -60 + 15x</em>
60 = 15x
x =
x = 4
put x = 4 in eq 1
we get y = 100 + 65 (4) = 100 + 260 = 360
x = 4, y = 360
Point of intersection: (x,y) = (4,360)