All categories

3 years ago

Which expression is the factored from of 2/3x + 4? Please help ASAP

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

Answer:

2/3 (x+6)

Step-by-step explanation:

To factor the expression, remove 2/3 from each term and write it outisde of the parenthesis. Divide each term by 2/3 to find the factors.

So 2/3 x +4 becomes 2/3(x+6).

You might be interested in

You are playing a card game with friends. at one point. you double your score. in the next hand you lose 75 points. you end up w

Gnoma [55]

Answer:

i) x points; ii) 2x - 75 = -25; iii) x = 25

Step-by-step explanation:

i) Starting points

Let's say you had x points before doubling your score.

(ii) The equation

After doubling score: 2x points

After losing 75 points: (2x - 75) points

At end of game: -25 points

The equation is

2x - 75 = -25

iii) Solution to equation

2x - 75 = -25 Add 75 to each side

2x = 50 Divide each side by 2

x = 25

3 0

4 years ago

Vector vector a has a magnitude of 28 units and points in the positive y-direction. When vector vector b is added to vector a ,

Triss [41]

28 + vector b = -12

vector b = -40

vector b has magnitude 40 units in the negative y direction.

5 0

3 years ago

Divide. (10a^4-5a^3) / 5a

wolverine [178]

$\boxed{\frac{10a^4-5a^3}{ 5a}=\frac{10a^4}{5a}-\frac{5a^3}{5a}=2a^3-a^2}$

5 0

3 years ago

Pls help.....................

scZoUnD [109]

Answer:

351 carrots

Step-by-step explanation:

13 = 1 tens + 3 units

27 = 2 tens + 7 units

13 × 27 = 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27 + 27

13 × 27 = 351

Conclusion:

Total Carrots is 351 carrots.

4 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let X = number of vehicles that pass the inspection.

The probability of the random variable X is P (X) = 0.70.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let X = all 3 vehicle passes and Y = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

3 years ago