Answer:
The length of the flag is 730 ft and the width is 310 ft
Step-by-step explanation:
<u><em>The correct question is</em></u>
The perimeter of the flag is 2080 ft what is the flags width and length <u>if</u> the length is 420 ft greater than the width
Let
L ----> the length of the flag
W ---> the width of the flag
we know that
The perimeter of the flag (rectangle) is equal to
![P=2(L+W)](https://tex.z-dn.net/?f=P%3D2%28L%2BW%29)
we have
![P=2,080\ ft](https://tex.z-dn.net/?f=P%3D2%2C080%5C%20ft)
so
![2,080=2(L+W)](https://tex.z-dn.net/?f=2%2C080%3D2%28L%2BW%29)
----> equation A
---> equation B
Solve the system by substitution
substitute equation B in equation A
solve for W
<em>Find the value of L</em>
----> ![L=310+420=730\ ft](https://tex.z-dn.net/?f=L%3D310%2B420%3D730%5C%20ft)
therefore
The length of the flag is 730 ft and the width is 310 ft
Yep! They are all right! Great job, could write a bit better.... sorry
The value of x would have to be 90 degrees as it is a right angle.
Thank you,
Jolly Santa