Can someone please answer. There is one problem. There's a picture. Thank you!

A cube measures 6.6 inches on each side. Find the volume of the cube.

ELEN [110]

287.496 in^3 since you take 6.6 * 6.6 *6.6 that should give you your answer

4 0

4 years ago

Find the slope of this line

tester [92]

Answer:

Points (3, 3) and (5, 4)

4 - 3 1

____ = _____ = 1/2, A is your answer

5 - 3 2

5 0

3 years ago

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Mrs Leon bought 6 rolls of toilet paper and 5 bottles of hand sanitizer for $32. Ms Ramirez bought 4 rolls of toilet paper and 1

zlopas [31]

Answer:

The cost of a roll of toilet paper is $2 and the cost of a bottle of hand sanitizer is $4.

Step-by-step explanation:

Given:

Mrs Leon bought 6 rolls of toilet paper and 5 bottles of hand sanitizer for $32.

Ms Ramirez bought 4 rolls of toilet paper and 1 bottle of hand sanitizer for $12.

Now, to find the cost for each item sold.

Let the cost of a roll of toilet paper be $x.$

And the cost of a bottle of hand sanitizer be $y.$

So, the cost of 4 rolls of toilet paper and 1 bottle of hand sanitizer:

$4x+y=12\\\\y=12-4x\ \ \ \ .....(1)$

Now, the cost of 6 rolls of toilet paper and 5 bottles of hand sanitizer:

$6x+5y=32$

Substituting the value of $y$ from equation (1):

$6x+5(12-4x)=32$

$6x+60-20x=32$

$60-14x=32$

Subtracting both sides by 60 we get:

$-14x=-28$

Dividing both sides by -14 we get:

$x=2.$

The cost of a roll of toilet paper = $2.

Now, substituting the value of $x$ in equation (1):

$y=12-4x\\\\y=12-4\times 2\\\\y=12-8\\\\y=4.$

The cost of a bottle of hand sanitizer = $4.

Therefore, the cost of a roll of toilet paper is $2 and the cost of a bottle of hand sanitizer is $4.

7 0

3 years ago

The decibel level of sound is 50 dB greater on a busy street than in a quiet room where the intensity of sound is watt/m2. The l

makkiz [27]

Complete question is;

The decibel level of sound is 50 dB greater on a busy street than in a quiet room where the intensity of sound is 10^-10 watt/m2. The level of sound in the quiet room is (10,20,100) dB, and the intensity of sound in the busy street is (10^-1, 10^-5, 10^-10) watt/m2.

Use the formula , β = 10log I/I 0 where β is the sound level in decibels, I is the intensity of sound you are measuring, and Io is the smallest sound intensity that can be heard by the human ear (roughly equal to 1 x 10^-12 watts/m2).

Answer:

A) The level of sound in the quiet room will be 20 dB

B) The intensity of sound in the busy street is 10⁻⁵ W·m⁻²

Step-by-step explanation:

Formula given is; β = 10log(I/I₀)

(a) For Quiet room:

We are given;

I = 10⁻¹⁰ W·m⁻²

I₀ = 1 × 10⁻¹² W·m⁻²

Plugging these values into the given equation, we have;

β = 10log[(10⁻¹⁰/(1 × 10⁻¹²)]

β = 10log(10²)

β = 10 × 2 = 20 dB

Thus, the level of sound in the quiet room will be 20 dB.

(b) For the Street;

We are given;

β(street) - β(room) = 50 dB

Now, let's rewrite the given intensity level equation;

β = 10logI - 10 logI₀

Now, Let the intensity level for the room be β₁ and let the intensity level for the road be β₂. Thus;

β₁ = 10logI₁ - 10log I₀ - - - - (eq 1)

β₂ = 10logI₂ - 10logI₀ - - - - (eq 2)

Subtract eq 1 from eq 2 to give;

β₂ - β₁ = 10logI₂ - 10logI₁

50 = 10logI₂ - 10log(10⁻¹⁰)

Divide each term by 10 to give:

5 = logI₂ - log(10⁻¹⁰)

5 = logI₂ - (-10)

5 = logI₂ + 10

Subtract 10 from each side to give;

-5 = logI₂

Taking the antilog of both sides to give;

I₂ = 10⁻⁵ W·m⁻²

Thus, the intensity of sound in the busy street is 10⁻⁵ W·m⁻².

7 0

4 years ago

Triangle ABC is shown below.

zhannawk [14.2K]

Answer:

b

Step-by-step explanation:

3 0

4 years ago

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