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sladkih [1.3K]
3 years ago
7

18 out of the 48 students in the class are left handed. What percent of the class is left handed?

Mathematics
2 answers:
bogdanovich [222]3 years ago
8 0

Answer:

37,5%

Step-by-step explanation:

48----100%

18------x

X=(18 × 100)/48

X=37,5%

balu736 [363]3 years ago
7 0

Answer: 38% of the class is left handed.

Step-by-step explanation:

The first step is to set up the equation:

18/48 = x/100

The second step is to set solve the equation:

18/48 = x/100

Cross multiply:

18 × 100 = 1800

48 × x = 48x

So,

1800 = 48x

Then divide 48 on each side to isolate the variable:

1800/48 = 48x/48

37.5 = x

x = 37.5

Since you can not have half a person, you must round the percentage from 37.5% ⇒ 38%.

I hope I helped and have a great day! ^-^

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Answer:if there are 7 HS students for every 2 MS students and there are 18 MS students...

18/2 = 9

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So, there are 18 + 63 = 81 total students.

Since we had 9 parts last year also (1:8), 81/9 = 9 students are in each part. 8 students in each part are HS and one is MS.

8(9) = 72 HS students last year.

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Hope this helps!

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Rudik [331]

Answer:

The answer to the question is

μx + (σx/4)

Step-by-step explanation:

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The standard error of the mean is

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The standard of error is an indication of the expected error in the mean of a sample from the mean of the population.

The above statements is based on the central limit theorem, which states that, in particular instances the normalized sum of independent random variables becomes closer and closer to those of  normal distribution regardless of the variation in the sample of the variables

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Answer:

2

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