All categories

3 years ago

Please answer quickly.

Mathematics

1 answer:

Ivanshal [37]3 years ago

8 0

Answer:

1) the constant variation is B) -2

3) the equation of the line is C) y=2/3x+9

4) the equation of the line is D) y=2x-5

You might be interested in

Evaluate the following. 4x4+6divided by2-5

LenKa [72]

Factor the numerator and denominator and cancel the common factors.
4x^4 - 2

8 0

2 years ago

Read 2 more answers

PLEASE HURYYYY <br>Solve the inequality.<br><br>−2 <m – 7

soldi70 [24.7K]

Here you go, hope it helps:)

6 0

3 years ago

Read 2 more answers

Each container has a base of 4 1/4 yds by 1 2/3 yds. What is the area covered by all the containers?

svet-max [94.6K]

Answer:

See Explanation

Step-by-step explanation:

Given

Base Dimension

$Length = 4\frac{1}{4}yd$

$Width = 1\frac{2}{3}yd$

Required

The base area of all containers

First, calculate the base area of 1 container.

This is calculated as:

$Area = Length * Width$

$Area = 4\frac{1}{4}yd * 1\frac{2}{3}yd$

Express as improper fraction

$Area = \frac{17}{4}yd * \frac{5}{3}yd$

So, we have:

$Area = \frac{17*5}{4*3}yd^2$

$Area = \frac{85}{12}yd^2$

The number of containers is not given. So, I will use 'n' as the number of containers.

So, we have:

$Total = n * Area$

$Total= n * \frac{85}{12}yd^2$

--------------------------------------------------------------------------------------------

Assume n is 3 (i.e. 3 containers)

The total area is:

$Total= 3 * \frac{85}{12}yd^2$

$Total= \frac{85}{4}yd^2$

$Total= 21\frac{1}{4}yd^2$

--------------------------------------------------------------------------------------------

6 0

3 years ago

Measure of angle ABD =5x, measure of angle DBC =3x+10 solve for x and find measure of angle ABC

Lelechka [254]

5......................................

6 0

3 years ago

The graph of g(x)=(0.5)x+4 is shown. Which equation is an asymptote of this function? y = 0 y = 4 x = 4 x = 0

Alexandra [31]

we are given

$g(x)=(0.5)^x+4$

we can see that

there is no value of x for which g(x) is not defined

so, no vertical asymptote exists

now, we will find horizontal asymptote

$\lim_{x \to \infty} g(x)= \lim_{x \to \infty}((0.5)^x+4 )$

$\lim_{x \to \infty} g(x)= (\lim_{x \to \infty} (0.5)^x+\lim_{x \to \infty} 4 )$

$\lim_{x \to \infty} g(x)= 0+4$

so, we get

horizontal asymptote as

$y= 4$ ............Answer

3 0

2 years ago