Vertex: <span><span>(0,0)</span><span>(0,0)</span></span>Focus: <span><span>(1,0)</span><span>(1,0)</span></span>Axis of Symmetry: <span><span>y=0</span><span>y=0</span></span>Directrix: <span>x=−<span>1</span></span>
Answer:
G. -5/2
Step-by-step explanation:
First we want to distribute the 6 into q and 3.
6q + 18 = 2(q + 4)
Next distribute the 2 into q and 4.
6q + 18 = 2q + 8
Now the variable needs to be on one side of the equation. Subtract 2q from both sides.
4q + 18 = 8
Isolate the variable. Subtract 18 from both sides.
4q = -10
Divide 4 on both sides.
q = -10/4
We can now simplify this even further. Divide -10/4 by 2/2
q = -5/2
Y = -2/3x + 5....the slope here is -2/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, we flip the slope and change the sign. So our perpendicular line will have a slope of 3/2 (see how I flipped -2/3 making it -3/2....and then changed the sign, making it 3/2)
y = mx + b
slope(m) = 3/2
(8,1)....x = 8 and y = 1
now we sub and find b, the y int
1 = 3/2(8) + b
1 = 12 + b
1 - 12 = b
-11 = b
so ur perpendicular equation is : y = 3/2x - 11 <==
Answer:
see description
Step-by-step explanation:
When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed). Notice that B is 5 horizontal units to the right of the y-axis, and B' is 5 horizontal units to the left of the y-axis.
