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matrenka [14]
3 years ago
12

A student performed the following system to find the solution to the equation x2-2x-8=0

Mathematics
2 answers:
Molodets [167]3 years ago
5 0

The student messed up on step one. The proper factoring is (x-4) (x+2)

Vsevolod [243]3 years ago
3 0

Answer:

B. in step 1

Step-by-step explanation:

Given that a student performed the following steps to find the solution of the quadratic equation x^2-2x-8=0.

Step 1: Factor the polynomial into (x-4) and (x-2).

Step 2: x-4=0 and x-2=0

Step 3: x=4 and x=2.

Now we need to find about which step has the error.

let's multiply (x-4) and (x-2)

we get : (x-4)(x-2)=x^2-4x-2x+8=x^2-8x+8

While original problem has -8 as the last term. So that means factors are wrong.

Hence choice B. in step 1. is correct

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Which expression is equivalent to 15a^8b^4/5a^4b?<br> 3a^2b^4<br> 3a^4b^3<br> 10a^4b^3<br> 10a^4b^4
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Step-by-step explanation:

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