1 year ago

Answer 396,397,398,399

Mathematics

1 answer:

ololo11 [35]1 year ago

6 0

Answer:

yes you are right I think

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Time to land on 11ft is 4.25 seconds

Step-by-step explanation:

Given

$y = 300 - 16t^2$

Required

Solve for t when height is 11ft

This implies that $y = 11$

So: substitute 11 for y in $y = 300 - 16t^2$

$11 = 300 - 16t^2$

Collect Like Terms

$16t^2 = 300 - 11$

$16t^2 = 289$

Express both sides as squares

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$(4t)^2 = 17^2$

Take square roots of both sides (ignore negative)

$4t = 17$

Solve for t

$t = \frac{17}{4}$

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Hence, time to land on 11ft is 4.25 seconds

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