Answer 396,397,398,399
1 answer:
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Answer:
The dimension of the open rectangular box is .
The volume of the box is 8.217 cubic inches.
Step-by-step explanation:
Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 11 in. by 7 in. by cutting congruent squares from the corners and folding up the sides.
To find : The dimensions and the volume of the open rectangular box ?
Solution :
Let the height be 'x'.
The length of the box is '11-2x'.
The breadth of the box is '7-2x'.
The volume of the box is
Derivate w.r.t x,
The critical point when V'(x)=0
Solve by quadratic formula,
Derivate again w.r.t x,
Now, (+ve)
(-ve)
So, there is maximum at x=1.392.
The length of the box is
The breadth of the box is
The height of the box is h=1.392.
The dimension of the open rectangular box is .
The volume of the box is
The volume of the box is 8.217 cubic inches.
Answer:
8.0
Step-by-step explanation:
The triangle is a right triangle, so we are able to use trigonometric functions. Relative to the angle of 37°, we have the opposite side which is 6 and the adjacent side which is x. The trig function that uses the opposite and adjacent is tangent(SohCahToa). We can set up the following equation:
tan(37) evaluates to about , so we can plug it in and solve for x:
To the nearest tenth, x rounds to 8.0.